SOP, POS, and de Morgan's theorem
Sum-of-products
- F' = A'B'C' + A'BC' + AB'C'
Apply de Morgan's
- (F')' = (A'B'C' + A'BC' + AB'C')'
- F = (A + B + C) (A + B' + C) (A' + B + C)
Product-of-sums
- F' = (A+B+C')(A+B'+C')(A'+B+C')(A'+B'+C)(A'+B'+C')
Apply de Morgan's
- (F')' = ((A+B+C')(A+B'+C')(A'+B+C')(A'+B'+C)(A'+B'+C'))'
- F = A'B'C + A'BC + AB'C + ABC' + ABC