Reminder: WPL 2:30-4:30 today only on the 5th floor breakout of CSE
HW 6 Introduction
Lectures left:
Database querying
Database manipulation (create/insert)
Accessing SQL from PHP with the PDO object
grades
with student_id
)
SELECT col(s)
FROM table1, table2, ...
WHERE table1.a = table2.b
AND table2.c > '42';
SQL (template)
SELECT students.name, grades.*
FROM students, grades
WHERE students.id = grades.student_id
AND grades.grade > 'C';
SQL (example)
Result table
SELECT students.name, grades.*
FROM students, grades
WHERE students.id = grades.student_id
AND grades.grade > 'C';
SQL (example from previous slide)
A more compact solution (giving variable names to tables)
SELECT s.name, g.*
FROM students s, grades g
WHERE s.id = g.student_id
AND g.grade > 'C';
SQL (alternative example)
SELECT s.name, g.*
FROM students s, grades g
WHERE s.id = g.student_id
AND g.grade > 'C';
SQL (example from previous slide)
SELECT s.name, g.*
FROM students s
JOIN grades g ON s.id = g.student_id
WHERE g.grade > 'C';
SQL (alternative example, using the JOIN keyword)
The JOIN
keyword is another way to join multiple tables. Some people find
this more intuitive, while others find joining tables on multiple WHERE conditions more
intuitive. Use whichever form you prefer most!
Note: There are other types of JOINS you may find on the recommended SQL query practice sites. You may learn these for fun if you'd like, but we don't cover it in this class (you will learn about them in other database courses). The JOIN keyword in this slide's example is also known as an "INNER JOIN"
Exercise: What courses have been taken by both Bart and Lisa?
SELECT bart.course_id
FROM grades bart, grades lisa
WHERE lisa.course_id = bart.course_id
AND bart.student_id = 123
AND lisa.student_id = 888;
SQL
What's wrong here?
What courses have been taken by both Bart and Lisa?
SELECT DISTINCT c.name
FROM courses c, students lisa, students bart, grades g1, grades g2
WHERE g1.course_id = c.id
AND g1.student_id = bart.id
AND g2.course_id = c.id
AND g2.student_id = lisa.id
AND bart.name = 'Bart'
AND lisa.name = 'Lisa';
SQL
Why so many tables?
student
and grades
information distinctly,
so we need to have two variables for each of these tables to join them correctly.Click for solutions
What are the names of all teachers Bart has had?
SELECT t.name
FROM teachers t
JOIN courses c ON c.teacher_id = t.id
JOIN grades g ON g.course_id = c.id
JOIN students s ON s.id = g.student_id
WHERE s.name = "Bart";
SQL
How many total students has Ms. Krabappel taught, and what are their names?
-- COUNT(s.name) gives the count
SELECT s.name
FROM students s
JOIN grades g ON s.id = g.student_id
JOIN courses c ON c.id = g.course_id
JOIN teachers t ON t.id = c.teacher_id
WHERE t.name="Krabappel";
SQL
What are the names of all teachers Bart has had?
SELECT t.name
FROM teachers t, students s, grades g, courses c
WHERE s.name="Bart"
AND s.id=g.student_id
AND g.course_id=c.id
AND c.teacher_id=t.id
SQL
How many total students has Ms. Krabappel taught, and what are their names?
-- COUNT(s.name) gives the count
SELECT s.name
FROM students s, grades g, courses c, teachers t
WHERE t.name="Krabappel"
AND t.id=c.teacher_id
AND c.id=g.course_id
AND g.student_id=s.id;
SQL
Figure out the proper SQL queries in the following way:
FROM
)SELECT
)JOIN
and/or WHERE
) and values
filtered (WHERE
)?DISTINCT
records?
imdb-small
is also provided on the query tester page for testing queries
with a smaller dataset
What are the names of all movies released in 1995?
How many people played a part in the movie "Lost in Translation"?
What are the names of all the people who played a part in the movie "Lost in Translation"?
Who directed the movie "Fight Club"?
How many movies has Clint Eastwood directed?
What are the names of all movies Clint Eastwood has directed?
What are the names of all directors who have directed at least one horror film?
What are the names of every actor who has appeared in a movie directed by Christopher Nolan?
SELECT name
FROM movies
WHERE year = 1995;
SQL
SELECT COUNT(*)
FROM actors a
JOIN roles r ON a.id = r.actor_id
JOIN movies m ON r.movie_id = m.id
WHERE m.name="Lost In Translation";
SQL
SELECT first_name, last_name
FROM actors a
JOIN roles r ON a.id = r.actor_id
JOIN movies m ON r.movie_id = m.id
WHERE m.name="Lost In Translation";
SQL
SELECT d.first_name, d.last_name
FROM directors d
JOIN movies_directors md ON md.director_id = d.id
JOIN movies m ON m.id = md.movie_id
WHERE m.name="Fight Club";
SQL
SELECT COUNT(*)
FROM movies m
JOIN movies_directors md ON md.movie_id = m.id
JOIN directors d ON md.director_id = d.id
WHERE d.first_name = "Clint"
AND d.last_name = "Eastwood";
SQL
SELECT m.name
FROM movies m
JOIN movies_directors md ON md.movie_id = m.id
JOIN directors d ON md.director_id = d.id
WHERE d.first_name = "Clint"
AND d.last_name = "Eastwood";
SQL
SELECT DISTINCT d.first_name, d.last_name
FROM directors d
JOIN movies_directors md ON md.director_id = d.id
JOIN movies_genres mg ON mg.movie_id = md.movie_id
WHERE mg.genre = "Horror";
SQL
SELECT DISTINCT a.first_name, a.last_name
FROM actors a
JOIN roles r ON a.id = r.actor_id
JOIN movies m ON m.id = r.movie_id
JOIN movies_directors md ON md.movie_id = m.id
JOIN directors d ON md.director_id = d.id
WHERE d.first_name = "Christopher"
AND d.last_name = "Nolan";
SQL
We do not cover JOINS in depth, but for more information you can look here