Assignment {v1=b1} is infeasible
{}
v1=b1
v1=c1
v2=b2
v2=c2
v3=b3
v3=c3
v1=b1
v2=b2
v1=b1
v2=c2
v1=b1
v3=c3
v1=b1
v3=b3
0
f({v1=b1}) is false
(v1=b1, v2=a2) is a conflict
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