There is no class today. You don’t need to turn in anything for this exercise. Do try them for yourself though!
Make sure you understand what would happen if the xv6 kernel executed the following code snippet:
Feel free to use QEMU to find out; acquire
is in spinlock.c
.
ide.c
An acquire
ensures interrupts are off on the local processor using
the cli
instruction (via pushcli()
), and interrupts remain off until
the release of the last lock held by that processor (at which point
they are enabled using sti
).
Let’s see what happens if we turn on interrupts while holding the
ide lock. In iderw
in ide.c
, add a call to sti()
after the
acquire()
, and a call to cli()
just before the release()
.
Rebuild the kernel and boot it in QEMU. Chances are the kernel will
panic soon after boot; try booting QEMU a few times if it doesn’t.
Try running QEMU on Linux.
Make sure you understand why the kernel panicked. You may find it
useful to look up the stack trace (the sequence of %eip
values
printed by panic) in the kernel.asm
listing.
file.c
Remove the sti()
and cli()
you added, rebuild the kernel, and make sure it works again.
Now let’s see what happens if we turn on interrupts while holding
the ftable.lock
. This lock protects the table of file descriptors,
which the kernel modifies when an application opens or closes a
file. In filealloc()
in file.c
, add a call to sti()
after the call
to acquire()
, and a cli()
just before each of the release()
es. You
will also need to add #include "x86.h"
at the top of the file after
the other #include
lines. Rebuild the kernel and boot it in QEMU.
It will not panic.
Why didn’t the kernel panic?
Why do ftable.lock
and ide_lock
have different behavior in this respect?
You do not need to understand anything about the details of the IDE hardware to answer this question, but you may find it helpful to look at which functions acquire each lock, and then at when those functions get called.
There is a very small but non-zero chance that the kernel will panic
with the extra sti()
in filealloc()
. If the kernel does panic, make
doubly sure that you removed the sti()
call from iderw
.
Why does release()
clear lk->pcs[0]
and lk->cpu
before clearing
lk->locked
? Why not wait until after?