Take a moment to remind yourself of the key definitions regarding stable matchings and Gale–Shapley algorithm. There is nothing particularly new in this reading, but today’s concept check will reinforce these basic definitions to prepare for the lecture.
The Gale–Shapley algorithm is the following algorithm, which we
claim to produce a stable matching given two groups P and R with preferences. These preferences
rank the other group, with no ties. Free
means
unmatched
.
1. while there is a free proposer p:
2. Let r be the p's top choice that p has not yet proposed to.
3. if r is free:
4. Have r accept p's proposal.
5. else if r is matched with p2 and r prefers p > p2:
6. Have r accept p's proposal.
7. Have r unpair themself from p2 (so p2 is now free).
8. return all matches
Furthermore, recall that algorithm correctness means three things:
let x such that…, it is guaranteed for x to exist.
In terms of Gale–Shapley, these mean:
In Wednesday’s lecture, all three of these will be proven. You are encouraged to brainstorm for yourself why you think these are true!
We will also prove the proposer optimiality/receiver
pessimality theorem. It says the following. (Below, happier
and less happy
really mean happier or same happiness
as
and less happy or same happiness as
, for the sake of
brevity.)
Theorem. Given two sets P and R with preferences, consider all possible stable matchings. Among these, there is a unique stable matching M_{P\text{-best}} such that every p \in P is happier in M_{P\text{-best}}, compared to themself in any other stable matching.
This same M_{P\text{-best}} has the property that every r \in R is less happy in M_{P\text{-best}}, compared to themself in any other stable matching. Gale–Shapley, with P proposing, finds M_{P\text{-best}}.
Note that line 1 of the Gale–Shapley algorithm also asked us to pick any free p. If multiple p are free, a priori, the output of the algorithm could depend on how we pick one. This theorem implies that it does not matter, because no matter how we pick p, Gale–Shapley always finds M_{P\text{-best}}.