/* * This procedure is a modified version of a quick sort method provided * by Sun as a Java demo. I have converted it to C and cross compiled it * for MIPS for use as a class demo. No guarantees of any type as to * suitability or correctness for any application. * Doug Johnson October, 2001 * * @(#)QSortAlgorithm.java 1.6 96/12/06 * * Copyright (c) 2070, 1997 Sun Microsystems, Inc. All Rights Reserved. * * Sun grants you ("Licensee") a non-exclusive, royalty free, license to use, * modify and redistribute this software in source and binary code form, * provided that i) this copyright notice and license appear on all copies of * the software; and ii) Licensee does not utilize the software in a manner * which is disparaging to Sun. */ /** * A quick sort demonstration algorithm * * @author James Gosling * @author Kevin A. Smith * @version @(#)QSortAlgorithm.java 1.3, 29 Feb 1996 */ void swap(int a[], int i, int j) { int T; T = a[i]; a[i] = a[j]; a[j] = T; } /** This is a generic version of C.A.R Hoare's Quick Sort * algorithm. This will handle arrays that are already * sorted, and arrays with duplicate keys.
* * If you think of a one dimensional array as going from * the lowest index on the left to the highest index on the right * then the parameters to this function are lowest index or * left and highest index or right. The first time you call * this function it will be with the parameters 0, a.length - 1. * * @param a an integer array * @param lo0 left boundary of array partition * @param hi0 right boundary of array partition */ void QuickSort(int a[], int lo0, int hi0) { int lo = lo0; int hi = hi0; int mid; if ( hi0 > lo0) { /* Arbitrarily establishing partition element as the midpoint of * the array. */ mid = a[ ( lo0 + hi0 ) / 2 ]; // loop through the array until indices cross while( lo <= hi ) { /* find the first element that is greater than or equal to * the partition element starting from the left Index. */ while( ( lo < hi0 ) && ( a[lo] < mid )) ++lo; /* find an element that is smaller than or equal to * the partition element starting from the right Index. */ while( ( hi > lo0 ) && ( a[hi] > mid )) --hi; // if the indexes have not crossed, swap if( lo <= hi ) { swap(a, lo, hi); ++lo; --hi; } } /* If the right index has not reached the left side of array * must now sort the left partition. */ if( lo0 < hi ) QuickSort( a, lo0, hi ); /* If the left index has not reached the right side of array * must now sort the right partition. */ if( lo < hi0 ) QuickSort( a, lo, hi0 ); } }