// simple program that shows that a type error can occur even without
// pointers or casting when local variables are not intialized, which
// means that the uninitialized variable is interpreting the bits in a
// different way.  If you compile with the -Wall option, you get a
// warning.

#include <iostream>
using namespace std;
        
void foo() {
    char text[4];
    text[0] = 'f';
    text[1] = 'u';
    text[2] = 'n';
    text[3] = '\0';
    cout << text << endl;
}
        
void bar() {
    int n;
    cout << n << endl;
}
        
int main() {
    foo();
    bar();
        
    return 0;
}