Sample answers for the given trace when simulating the first 25 instructions: Forwarding EX/MEM to ID/EX for instructions 1 to 2 Forwarding EX/MEM to ID/EX for instructions 3 to 4 Load stall for 1 cycle at instruction 5 Forwarding MEM/WB to ID/EX for instructions 4 to 5 Forwarding MEM/WB to ID/EX for instructions 5 to 7 Forwarding EX/MEM to ID/EX for instructions 7 to 8 Forwarding EX/MEM to ID/EX for instructions 8 to 9 Load stall for 1 cycle at instruction 13 Forwarding MEM/WB to ID/EX for instructions 12 to 13 Forwarding EX/MEM to ID/EX for instructions 14 to 15 Branch stall for 2 cycles at instruction 17 Forwarding EX/MEM to ID/EX for instructions 15 to 16 Load stall for 1 cycle at instruction 18 Forwarding MEM/WB to ID/EX for instructions 17 to 18 Forwarding EX/MEM to ID/EX for instructions 19 to 20 Branch stall for 2 cycles at instruction 22 Forwarding EX/MEM to ID/EX for instructions 20 to 21 Load stall for 1 cycle at instruction 23 Forwarding MEM/WB to ID/EX for instructions 22 to 23 Forwarding EX/MEM to ID/EX for instructions 24 to 25 Number of cycles: 37 Stalled for a total of 8 cycles Forwarded 14 times Distribution of opcodes: ADD: 4 SLL: 1 SLT: 3 ADDI: 7 ORI: 1 LUI: 2 LW: 5 BNE: 2 This is the first 25 instructions of the disassembled trace: 1 lui \$1,4097 #la \$a0,array 2 ori \$4,\$1,124 3 lui \$1,4097 #lw \$a1,size 4 lw \$5,120(\$1) 5 sll \$5,\$5,2 #sll \$a1,\$a1,2 6 addi \$8,\$0,0 #addi \$t0,\$t0,0 7 addi \$9,\$5,-4 #addi \$t1,\$a1,-4 8 add \$6,\$4,\$9 #add \$a2,\$a0,\$t1 9 lw \$9,0(\$6) #lw \$t1,0(\$a2) 10 addi \$13,\$0,0 #addi \$t5,\$0,0 11 addi \$12,\$0,0 #addi \$t4,\$0,0 12 lw \$16,0(\$6) #lw \$s0,0(\$a2) 13 add \$8,\$8,\$16 #add \$t0,\$t0,\$s0 14 addi \$12,\$12,4 #addi \$t4,\$t4,4 15 slt \$1,\$12,\$5 #blt \$t4,\$a1,loop 16 bne \$1,\$10,-5 17 lw \$16,0(\$6) #lw \$s0,0(\$a2) 18 add \$8,\$8,\$16 #add \$t0,\$t0,\$s0 19 addi \$12,\$12,4 #addi \$t4,\$t4,4 20 slt \$1,\$12,\$5 #blt \$t4,\$a1,loop 21 bne \$1,\$10,-5 22 lw \$16,0(\$6) #lw \$s0,0(\$a2) 23 add \$8,\$8,\$16 #add \$t0,\$t0,\$s0 24 addi \$12,\$12,4 #addi \$t4,\$t4,4 25 slt \$1,\$12,\$5 #blt \$t4,\$a1,loop Note that the actual source program only had one loop: 1 lui \$1,4097 #la \$a0,array 2 ori \$4,\$1,124 3 lui \$1,4097 #lw \$a1,size 4 lw \$5,120(\$1) 5 sll \$5,\$5,2 #sll \$a1,\$a1,2 6 addi \$8,\$0,0 #addi \$t0,\$t0,0 7 addi \$9,\$5,-4 #addi \$t1,\$a1,-4 8 add \$6,\$4,\$9 #add \$a2,\$a0,\$t1 9 lw \$9,0(\$6) #lw \$t1,0(\$a2) 10 addi \$13,\$0,0 #addi \$t5,\$0,0 11 addi \$12,\$0,0 #addi \$t4,\$0,0 12 loop: lw \$16,0(\$6) #lw \$s0,0(\$a2) 13 add \$8,\$8,\$16 #add \$t0,\$t0,\$s0 14 addi \$12,\$12,4 #addi \$t4,\$t4,4 15 slt \$1,\$12,\$5 #blt \$t4,\$a1,loop 16 bne \$1,\$10,loop Its purpose was to multiply the last element of an array by the number of elements in the array.