Solutions
Memory: Address Contents 000000ac Page Table Address: 0000e0a8 000000b0 000000b4 . . . 000080ac 000080b0 000080b4 . . . 0000e0ac 80000000 0000e0b0 8000000e 0000e0b4 8000a0b4
Q. Assuming 4K pages and "big-endian" addressing, i.e. the 0 byte of a word is the msb end, what are the contents of the memory location at the virtual address 000020b7?
A. "0b7" is the page offset, and "00002" is the virtual page number. Convert this to a displacement for the page table by multiplying by 4, and add to the page table address:
0000e0a8 + 8 = 0000e0b0". Find the physical page number at that location: 8000000e, where the msb is the "valid bit". Construct the physical address: 0000e0b7. Find that byte in memory: b4.