Computing the Cycle Time
Suppose the following times apply ...
Memory units: 10ns
ALU and adders: 10ns
Register file ref: 5ns
All other operations are 0ns.
Charges for instructions are ...
R-format: 30ns
Load inst: 40ns
Store inst: 35ns
Branch: 25ns
Jump: 10ns
CPU Clock Cycle = 40x.22+35x.11+30x.49+25x.16+10x.02=31.6
CPU Perfv/CPU Perfs = 40/31.6=1.27