Long example
A’B’C’D’ + A’BC’D’ + A’BD + A’BC’D + ABCD + ACD’ + B’CD’
= A’C’D’(B’ + B) + A’BD(1 + C’) + ABCD + ACD’ + B’CD’
= A’C’D’ + A’BD + ABCD + ACD’ + B’CD’
= A’C’D’ + BD(A’ + AC) + ACD’ + B’CD’
= A’C’D’ + BD(A’ + C) + ACD’ + B’CD’ (Since X + X’Y = X + Y)
= A’C’D’ + A’BD + (BCD + ACD’) + B’CD’
= A’C’D’ + A’BD + (BCD + ACD’ + ABC) + B’CD’
= A’C’D’ + (A’BD + ABC + BCD) + (ABC + B’CD’ + ACD’)
= AC’D’ + A’BD + ABC + B’CD’