(define fn '*) (define x 3) (define y (list '+ x 5)) (define z (list fn 10 y)) x => 3 y => (+ 3 5) z => (* 10 (+ 3 5)) (eval '(+ 6 6) user-initial-environment) => 12 (eval y user-initial-environment) => 8 (eval z user-initial-environment) => 80An example of variables whose values are atoms:
(define a 'b) (define b 'c) (define c 50) a => b (eval a user-initial-environment) => c (eval (eval a user-initial-environment) user-initial-environment) => 50The top level of the Scheme interpreter is a read-eval-print loop: read in an expression, evaluate it, and print the result.
user-initial-environment is bound to an environment and is pre-defined. There are also functions to get the environment for any procedure, etc. See the MIT Scheme User's Manual section on read-eval-print loop.
Quote suppresses evaluation; eval causes evaluation. They can cancel each other out.
(define x 3) x => 3 'x => x (eval 'x user-initial-environment) => 3
(apply factorial '(3)) => 6 (apply + '(1 2 3 4)) => 10A useful programming trick is to use apply to define a function that takes a list of arguments, if you have available a function that arbitrary number of arguments. Example:
(define (sum s) (apply + s)) (sum '(1 2 3)) => 6