```/*
*
*  This file is the solution to an exercise problem posed during
*  one of the UW CSE 333 lectures (333exercises).
*
*  333exercises is free software: you can redistribute it and/or modify
*  the Free Software Foundation, either version 3 of the License, or
*  (at your option) any later version.
*
*  333exercises is distributed in the hope that it will be useful,
*  but WITHOUT ANY WARRANTY; without even the implied warranty of
*  MERCHANTABILITY or FITNESS FOR A PARTICULAR PURPOSE.  See the
*  GNU General Public License for more details.
*
*  You should have received a copy of the GNU General Public License
*  along with 333exercises.  If not, see <http://www.gnu.org/licenses/>.
*/

// Lecture 3 exercise 3

#include <stdio.h>   // needed for printf
#include <stdlib.h>  // needed for malloc, free
#include <assert.h>  // needed for assert

// Write a function that:
//
//  - accepts an (array of ints) and an (array length) as arguments
//
//  - mallocâ€™s an (array of (int *)) of the same length
//
//  - initializes each element of the newly allocated array to point to
//    the corresponding element in the passed-in array
//
//  - returns a pointer to the newly allocated array

int **MakePointerArray(int *intarray, int arraylen) {
int **parray;
int   i;

// do some sanity checking on the arguments
assert(intarray != NULL);
assert(arraylen > 0);

// malloc the array, make sure we had the memory for it
parray = (int **) malloc(arraylen*sizeof(int *));
assert(parray != NULL);

// initialize the array
for (i=0; i<arraylen; i++) {
parray[i] = &(intarray[i]);
}

// return the array
return parray;
}

int main(int argc, char **argv) {
int **parray = NULL;
int   intarray[2] = {1, 2};

parray = MakePointerArray(intarray, 2);
assert(parray != NULL);
assert(parray[0] == &(intarray[0]));
assert(parray[1] == &(intarray[1]));
free(parray);

return 0;
}
```