/* * Copyright 2011 Steven Gribble * * This file is the solution to an exercise problem posed during * one of the UW CSE 333 lectures (333exercises). * * 333exercises is free software: you can redistribute it and/or modify * it under the terms of the GNU General Public License as published by * the Free Software Foundation, either version 3 of the License, or * (at your option) any later version. * * 333exercises is distributed in the hope that it will be useful, * but WITHOUT ANY WARRANTY; without even the implied warranty of * MERCHANTABILITY or FITNESS FOR A PARTICULAR PURPOSE. See the * GNU General Public License for more details. * * You should have received a copy of the GNU General Public License * along with 333exercises. If not, see . */ // Lecture 2 exercise 2: // // Write a function that: // - accepts a function pointer and an integer as an argument // - invokes the pointed-to function, with the integer as its argument #include // needed for the definition of NULL, printf #include // needed for the definition of assert() // The C syntax for function pointers is pretty confusing. // Read the manual (CARM); I've also found this web page // to be pretty helpful: // // http://www.newty.de/fpt/index.html // void InvokeFunction(void (*f)(int), int arg) { assert(f != NULL); f(arg); } // Here's some code to test our function void FirstFunction(int a) { printf("In FirstFunction with argument '%d'\n", a); } void SecondFunction(int b) { printf("In SecondFunction with argument '%d'\n", b); } void ThirdFunction(int c) { printf("In ThirdFunction with argument '%d'\n", c); } int main(int argc, char **argv) { void (*g)(int); InvokeFunction(&FirstFunction, 5); InvokeFunction(&SecondFunction, 6); g = &ThirdFunction; InvokeFunction(g, 7); return 0; }