Total: 100 points
N3 + 100 N 100 N4 + N log N 2 N2 + N + 2100 3 log log N + log2 N log log (N2) + 3 log2 (N2) 10 N2 + 5 N + N3 log N 2.5N + N100
int fun_a(int N) { if (N<=1) return 100; else return 2*fun_a(N-1); } int fun_b(int N) { if (N<=1) return 100; else return fun_b(N/2) * fun_b(N/2 - 1); }