/*
CSE 303, Spring 2009, Marty Stepp
This program uses heap memory allocation (malloc) to return a copy of an array.
*/

#include <stdio.h>
#include <stdlib.h>

int* copy(int a[], int size);

int main(void) {
    int i;
    int nums[4] = {7, 4, 3, 5};
    int* nums2 = copy(nums, 4);
    
    // print the values from the copy array to make sure it worked
    for (i = 0; i < 4; i++) {
        printf("nums2[%d] is %d\n", i, nums2[i]);
    }
    
    // we should free all our malloc'd memory
    // (though in this case it doesn't matter much because the program is about
    // to exit anyway, at which point the memory would be reclaimed)
    free(nums2);
    nums2 = NULL;
    
    return 0;
}

/* Returns a new heap-allocated array that is a copy of the given array. */
int* copy(int a[], int size) {
    int i;
    int* a2 = malloc(size * sizeof(int));
    for (i = 0; i < size; i++) {
        a2[i] = a[i];
    }
    return a2;
}