Neural Networks¶
In this lesson, we'll learn how to train two kinds of artificial neural networks to detect handwritten digits in an image. By the end of this lesson, students will be able to:
- Identify neural network model parameters and hyperparameters.
- Determine the number of weights and biases in a multilayer perceptron and convolutional neural network.
- Explain how the layers of a convolutional neural network extract information from an input image.
First, let's watch the beginning of 3Blue1Brown's introduction to neural networks while we wait for the imports and dataset to load. We'll also later explore the TensorFlow Playground to learn more about neural networks from the perspective of linear models.
%%html
<iframe width="640" height="360" src="https://www.youtube-nocookie.com/embed/aircAruvnKk?start=163&end=331" title="YouTube video player" frameborder="0" allow="accelerometer; autoplay; clipboard-write; encrypted-media; gyroscope; picture-in-picture; web-share" allowfullscreen></iframe>
For this lesson, we'll re-examine machine learning algorithms from scikit-learn. We'll also later use keras
, a machine learning library designed specifically for building complex neural networks.
!pip install -q keras tensorflow-cpu
!pip install -q keras tensorflow-cpu
from sklearn.datasets import fetch_openml
from sklearn.model_selection import train_test_split
from sklearn.neural_network import MLPClassifier
import matplotlib.pyplot as plt
We'll be working with the MNIST dataset, which is composed of 70,000 images of handwritten digits, of which 60,000 were drawn from employees at the U.S. Census Bureau and 10,000 drawn from U.S. high school students.
In the video clip above, we saw how to transform an image from a 28-by-28 square to a 784-length vector that takes each of the 28 rows of 28-wide pixels and arranges them side-by-side in a line. This process flattens the image from 2 dimensions to 1 dimension.
X, y = fetch_openml("mnist_784", version=1, return_X_y=True, parser="auto")
X = X / 255
X_train, X_test, y_train, y_test = train_test_split(X, y, test_size=0.2)
X
pixel1 | pixel2 | pixel3 | pixel4 | pixel5 | pixel6 | pixel7 | pixel8 | pixel9 | pixel10 | ... | pixel775 | pixel776 | pixel777 | pixel778 | pixel779 | pixel780 | pixel781 | pixel782 | pixel783 | pixel784 | |
---|---|---|---|---|---|---|---|---|---|---|---|---|---|---|---|---|---|---|---|---|---|
0 | 0.0 | 0.0 | 0.0 | 0.0 | 0.0 | 0.0 | 0.0 | 0.0 | 0.0 | 0.0 | ... | 0.0 | 0.0 | 0.0 | 0.0 | 0.0 | 0.0 | 0.0 | 0.0 | 0.0 | 0.0 |
1 | 0.0 | 0.0 | 0.0 | 0.0 | 0.0 | 0.0 | 0.0 | 0.0 | 0.0 | 0.0 | ... | 0.0 | 0.0 | 0.0 | 0.0 | 0.0 | 0.0 | 0.0 | 0.0 | 0.0 | 0.0 |
2 | 0.0 | 0.0 | 0.0 | 0.0 | 0.0 | 0.0 | 0.0 | 0.0 | 0.0 | 0.0 | ... | 0.0 | 0.0 | 0.0 | 0.0 | 0.0 | 0.0 | 0.0 | 0.0 | 0.0 | 0.0 |
3 | 0.0 | 0.0 | 0.0 | 0.0 | 0.0 | 0.0 | 0.0 | 0.0 | 0.0 | 0.0 | ... | 0.0 | 0.0 | 0.0 | 0.0 | 0.0 | 0.0 | 0.0 | 0.0 | 0.0 | 0.0 |
4 | 0.0 | 0.0 | 0.0 | 0.0 | 0.0 | 0.0 | 0.0 | 0.0 | 0.0 | 0.0 | ... | 0.0 | 0.0 | 0.0 | 0.0 | 0.0 | 0.0 | 0.0 | 0.0 | 0.0 | 0.0 |
... | ... | ... | ... | ... | ... | ... | ... | ... | ... | ... | ... | ... | ... | ... | ... | ... | ... | ... | ... | ... | ... |
69995 | 0.0 | 0.0 | 0.0 | 0.0 | 0.0 | 0.0 | 0.0 | 0.0 | 0.0 | 0.0 | ... | 0.0 | 0.0 | 0.0 | 0.0 | 0.0 | 0.0 | 0.0 | 0.0 | 0.0 | 0.0 |
69996 | 0.0 | 0.0 | 0.0 | 0.0 | 0.0 | 0.0 | 0.0 | 0.0 | 0.0 | 0.0 | ... | 0.0 | 0.0 | 0.0 | 0.0 | 0.0 | 0.0 | 0.0 | 0.0 | 0.0 | 0.0 |
69997 | 0.0 | 0.0 | 0.0 | 0.0 | 0.0 | 0.0 | 0.0 | 0.0 | 0.0 | 0.0 | ... | 0.0 | 0.0 | 0.0 | 0.0 | 0.0 | 0.0 | 0.0 | 0.0 | 0.0 | 0.0 |
69998 | 0.0 | 0.0 | 0.0 | 0.0 | 0.0 | 0.0 | 0.0 | 0.0 | 0.0 | 0.0 | ... | 0.0 | 0.0 | 0.0 | 0.0 | 0.0 | 0.0 | 0.0 | 0.0 | 0.0 | 0.0 |
69999 | 0.0 | 0.0 | 0.0 | 0.0 | 0.0 | 0.0 | 0.0 | 0.0 | 0.0 | 0.0 | ... | 0.0 | 0.0 | 0.0 | 0.0 | 0.0 | 0.0 | 0.0 | 0.0 | 0.0 | 0.0 |
70000 rows × 784 columns
Because the MNIST dataset already comes flattened, if we want to display any one image, we need to reshape
it back to a 28-by-28 square.
plt.imshow(X.loc[0].to_numpy().reshape(28, 28), cmap="gray")
<matplotlib.image.AxesImage at 0x79ef0f9b9290>
Multilayer perceptrons¶
To create a neural network, scikit-learn provides an MLPClassifier
, or multilayer perceptron classifier, that can be used to match the video example with two hidden layers of 16 neurons each. While we wait for the training to complete, let's watch the rest of the video.
%%html
<iframe width="640" height="360" src="https://www.youtube-nocookie.com/embed/aircAruvnKk?start=332&end=806" title="YouTube video player" frameborder="0" allow="accelerometer; autoplay; clipboard-write; encrypted-media; gyroscope; picture-in-picture; web-share" allowfullscreen></iframe>
mlp_16x16 = MLPClassifier(hidden_layer_sizes=(16, 16), max_iter=5, verbose=True)
%time mlp_16x16.fit(X_train, y_train)
mlp_16x16.score(X_test, y_test)
Iteration 1, loss = 0.92632283 Iteration 2, loss = 0.33565057 Iteration 3, loss = 0.27750873 Iteration 4, loss = 0.24866184 Iteration 5, loss = 0.23040307 CPU times: user 9min 35s, sys: 1.63 s, total: 9min 37s Wall time: 4min 52s
/opt/conda/lib/python3.11/site-packages/sklearn/neural_network/_multilayer_perceptron.py:691: ConvergenceWarning: Stochastic Optimizer: Maximum iterations (5) reached and the optimization hasn't converged yet. warnings.warn(
0.9285714285714286
probs = mlp_16x16.predict_proba(X_test.head(1))
probs
array([[9.98221411e-01, 9.49217021e-10, 1.04587116e-03, 3.73570513e-07, 1.84343260e-07, 8.08504362e-05, 5.82896196e-04, 3.64064196e-06, 6.45884662e-05, 1.82960739e-07]])
for i, v in sorted(enumerate(probs[0]), key=lambda x: x[1], reverse=True):
print(f"{i}: {v:.4f}")
0: 0.9982 2: 0.0010 6: 0.0006 5: 0.0001 8: 0.0001 7: 0.0000 3: 0.0000 4: 0.0000 9: 0.0000 1: 0.0000
plt.imshow(X_test.iloc[1].to_numpy().reshape(28, 28), cmap="gray")
<matplotlib.image.AxesImage at 0x79ef0f118850>
Neural networks are highly sensistive to hyperparameter values such as the width and depth of hidden layers. Other hyperparameter values like the initial learning rate for gradient descent can also affect training efficacy. Early stopping is used to evaluate performance on a validation set accuracy (rather than training set loss) in order to determine when to stop training.
mlp_40 = MLPClassifier(hidden_layer_sizes=(40,), learning_rate_init=0.001, early_stopping=True, verbose=True)
%time mlp_40.fit(X_train, y_train)
mlp_40.score(X_test, y_test)
Iteration 1, loss = 0.60445835 Validation score: 0.906071 Iteration 2, loss = 0.27666377 Validation score: 0.925179 Iteration 3, loss = 0.22660441 Validation score: 0.933214 Iteration 4, loss = 0.19334185 Validation score: 0.942321 Iteration 5, loss = 0.16749608 Validation score: 0.945000 Iteration 6, loss = 0.14821941 Validation score: 0.947500 Iteration 7, loss = 0.13430439 Validation score: 0.953036 Iteration 8, loss = 0.12222141 Validation score: 0.954821 Iteration 9, loss = 0.11177124 Validation score: 0.958036 Iteration 10, loss = 0.10339358 Validation score: 0.959643 Iteration 11, loss = 0.09575611 Validation score: 0.959821 Iteration 12, loss = 0.08832224 Validation score: 0.959464 Iteration 13, loss = 0.08231870 Validation score: 0.961964 Iteration 14, loss = 0.07663748 Validation score: 0.961964 Iteration 15, loss = 0.07113307 Validation score: 0.963571 Iteration 16, loss = 0.06630588 Validation score: 0.965000 Iteration 17, loss = 0.06296239 Validation score: 0.965357 Iteration 18, loss = 0.05858014 Validation score: 0.964464 Iteration 19, loss = 0.05575241 Validation score: 0.963393 Iteration 20, loss = 0.05258834 Validation score: 0.966786 Iteration 21, loss = 0.04937947 Validation score: 0.966071 Iteration 22, loss = 0.04628569 Validation score: 0.966429 Iteration 23, loss = 0.04376740 Validation score: 0.965357
/opt/conda/lib/python3.11/site-packages/sklearn/neural_network/_multilayer_perceptron.py:698: UserWarning: Training interrupted by user. warnings.warn("Training interrupted by user.")
CPU times: user 1h 15min 16s, sys: 12.7 s, total: 1h 15min 29s Wall time: 37min 57s
0.9656428571428571
We can also visualize MLP weights (coefficients) on MNIST. These 28-by-28 images represent each of the 40 neurons in this single-layer neural network.
fig, axs = plt.subplots(nrows=4, ncols=10, figsize=(12.5, 5))
# Constrain plots to the same scale (divided by 2 for better display)
vmin, vmax = mlp_40.coefs_[0].min() / 2, mlp_40.coefs_[0].max() / 2
for ax, coef in zip(axs.ravel(), mlp_40.coefs_[0].T):
activations = coef.reshape(28, 28)
ax.matshow(activations, vmin=vmin, vmax=vmax)
ax.set_axis_off()
Convolutional neural networks¶
In the 3Blue1Brown video, we examined how a single neuron could serve as an edge detector. But in a plain multilayer perceptron, neurons are linked directly to specific inputs (or preceding hidden layers), so they are location-sensitive. The MNIST dataset was constructed by centering each digit individually in the middle of the box. In the real-world, we might not have such perfectly-arranged image data, particularly when we want to identify real-world objects in a complex scene (which is probably harder than identifying handwritten digits centered on a black background).
Convolutional neural networks take the idea of a neural network and applies it to learn the weights in a convolution kernel.
The following example, courtesy of François Chollet (the original author of Keras), shows how to load in the MNIST dataset using Keras.
import keras
from keras import layers, models
import matplotlib.pyplot as plt
import numpy as np
# Load the data as (N, 28, 28) images split between 80% train set and 20% test set
(X_train, y_train), (X_test, y_test) = keras.datasets.mnist.load_data()
# Scale image values from [0, 255] to [0, 1]
X_train = X_train.astype("float32") / 255
X_test = X_test.astype("float32") / 255
# Add an extra dimension to each image (28, 28, 1) as Keras requires at least 1 "color" channel
X_train = np.expand_dims(X_train, -1)
X_test = np.expand_dims(X_test, -1)
input_shape = (28, 28, 1)
assert X_train.shape[1:] == input_shape and X_test.shape[1:] == input_shape
# Convert a class vector (integers) to binary class matrix
num_classes = 10
y_train = keras.utils.to_categorical(y_train, num_classes)
y_test = keras.utils.to_categorical(y_test, num_classes)
# Display an image without any need to reshape
plt.imshow(X_train[0], cmap="gray")
2025-03-03 18:19:22.469255: I tensorflow/core/platform/cpu_feature_guard.cc:210] This TensorFlow binary is optimized to use available CPU instructions in performance-critical operations. To enable the following instructions: AVX2 FMA, in other operations, rebuild TensorFlow with the appropriate compiler flags.
<matplotlib.image.AxesImage at 0x7f16190df7d0>
The Keras Sequential
model allows us to specify the specific sequence of layers and operations to pass from one step to the next.
- The
Input
layer handles inputs of the given shape. - The
Conv2D
layer learns a convolution kernel withkernel_size
number of weights plus a bias. It outputs the given number offilters
, such as 32 or 64 used in the example below. - The
MaxPooling2D
layer to downsample the output from aConv2D
layer. The maximum value in each 2-by-2 window is passed to the next layer. - The
Flatten
layer flattens the given data into a single dimension. - The
Dropout
layer randomly sets input values to 0 at the given frequency during training to help prevent overfitting. (Bypassed during inference: evaluation or use of the model.) - The
Dense
layer is a regular densely-connected neural network layer like what we learned before.
Whereas MLPClassifier
counted an entire round through the training data as an iteration, Keras uses the term epoch to refer to the same idea of iterating through the entire training dataset and performing gradient descent updates accordingly. Here, each gradient descent update step examines 200 images each time, so there are a total of 270 update steps for the 54000 images in the training set.
# Build the model: in Keras, kernel_size is specified as (height, width)
kernel_size = (3, 3)
model = keras.Sequential([
keras.Input(shape=input_shape),
layers.Conv2D(32, kernel_size=kernel_size, activation="relu"),
layers.MaxPooling2D(pool_size=(2, 2)),
layers.Conv2D(64, kernel_size=kernel_size, activation="relu"),
layers.MaxPooling2D(pool_size=(2, 2)),
layers.Flatten(),
layers.Dropout(0.2),
layers.Dense(num_classes, activation="softmax"),
])
model.summary(line_length=80)
# Train and evaluate the model (same loss, gradient descent optimizer, and metric as MLPClassifier)
model.compile(loss="categorical_crossentropy", optimizer="adam", metrics=["accuracy"])
%time model.fit(X_train, y_train, batch_size=100, epochs=10, validation_split=0.1)
# Show the accuracy score on the test set
model.evaluate(X_test, y_test, verbose=0)[1]
Model: "sequential"
┏━━━━━━━━━━━━━━━━━━━━━━━━━━━━━━━━━━━┳━━━━━━━━━━━━━━━━━━━━━━━━━━┳━━━━━━━━━━━━━━━┓ ┃ Layer (type) ┃ Output Shape ┃ Param # ┃ ┡━━━━━━━━━━━━━━━━━━━━━━━━━━━━━━━━━━━╇━━━━━━━━━━━━━━━━━━━━━━━━━━╇━━━━━━━━━━━━━━━┩ │ conv2d (Conv2D) │ (None, 26, 26, 32) │ 320 │ ├───────────────────────────────────┼──────────────────────────┼───────────────┤ │ max_pooling2d (MaxPooling2D) │ (None, 13, 13, 32) │ 0 │ ├───────────────────────────────────┼──────────────────────────┼───────────────┤ │ conv2d_1 (Conv2D) │ (None, 11, 11, 64) │ 18,496 │ ├───────────────────────────────────┼──────────────────────────┼───────────────┤ │ max_pooling2d_1 (MaxPooling2D) │ (None, 5, 5, 64) │ 0 │ ├───────────────────────────────────┼──────────────────────────┼───────────────┤ │ flatten (Flatten) │ (None, 1600) │ 0 │ ├───────────────────────────────────┼──────────────────────────┼───────────────┤ │ dropout (Dropout) │ (None, 1600) │ 0 │ ├───────────────────────────────────┼──────────────────────────┼───────────────┤ │ dense (Dense) │ (None, 10) │ 16,010 │ └───────────────────────────────────┴──────────────────────────┴───────────────┘
Total params: 34,826 (136.04 KB)
Trainable params: 34,826 (136.04 KB)
Non-trainable params: 0 (0.00 B)
Epoch 1/10 540/540 ━━━━━━━━━━━━━━━━━━━━ 33s 54ms/step - accuracy: 0.8214 - loss: 0.6138 - val_accuracy: 0.9800 - val_loss: 0.0706 Epoch 2/10 540/540 ━━━━━━━━━━━━━━━━━━━━ 38s 51ms/step - accuracy: 0.9724 - loss: 0.0892 - val_accuracy: 0.9853 - val_loss: 0.0543 Epoch 3/10 540/540 ━━━━━━━━━━━━━━━━━━━━ 42s 53ms/step - accuracy: 0.9801 - loss: 0.0632 - val_accuracy: 0.9862 - val_loss: 0.0469 Epoch 4/10 540/540 ━━━━━━━━━━━━━━━━━━━━ 40s 51ms/step - accuracy: 0.9822 - loss: 0.0565 - val_accuracy: 0.9875 - val_loss: 0.0472 Epoch 5/10 540/540 ━━━━━━━━━━━━━━━━━━━━ 28s 51ms/step - accuracy: 0.9867 - loss: 0.0428 - val_accuracy: 0.9898 - val_loss: 0.0377 Epoch 6/10 540/540 ━━━━━━━━━━━━━━━━━━━━ 41s 52ms/step - accuracy: 0.9886 - loss: 0.0362 - val_accuracy: 0.9903 - val_loss: 0.0365 Epoch 7/10 540/540 ━━━━━━━━━━━━━━━━━━━━ 28s 52ms/step - accuracy: 0.9899 - loss: 0.0306 - val_accuracy: 0.9908 - val_loss: 0.0358 Epoch 8/10 540/540 ━━━━━━━━━━━━━━━━━━━━ 28s 51ms/step - accuracy: 0.9915 - loss: 0.0265 - val_accuracy: 0.9892 - val_loss: 0.0354 Epoch 9/10 540/540 ━━━━━━━━━━━━━━━━━━━━ 33s 62ms/step - accuracy: 0.9918 - loss: 0.0244 - val_accuracy: 0.9903 - val_loss: 0.0349 Epoch 10/10 540/540 ━━━━━━━━━━━━━━━━━━━━ 37s 54ms/step - accuracy: 0.9925 - loss: 0.0245 - val_accuracy: 0.9918 - val_loss: 0.0357 CPU times: user 8min 9s, sys: 49.2 s, total: 8min 58s Wall time: 6min
0.991100013256073
Practice: Multilayer perceptron in Keras¶
Write Keras code to recreate the two-hidden-layer multilayer perceptron model that we built using scikit-learn with the expression MLPClassifier(hidden_layer_sizes=(16, 16))
. For the hidden layers, specify activation="relu"
to match scikit-learn.
# Build the model
mlp_keras = keras.Sequential([
keras.Input(shape=input_shape), # (28, 28, 1)
layers.Flatten(),
# layers.Conv2D(32, kernel_size=kernel_size, activation="relu"),
# layers.MaxPooling2D(pool_size=(2, 2)),
# layers.Conv2D(64, kernel_size=kernel_size, activation="relu"),
# layers.MaxPooling2D(pool_size=(2, 2)),
# layers.Flatten(),
# layers.Dropout(0.2),
layers.Dense(16, activation="relu"),
layers.Dense(16, activation="relu"),
layers.Dense(num_classes, activation="softmax"),
])
mlp_keras.summary(line_length=80)
# Train and evaluate the model (same loss, gradient descent optimizer, and metric as MLPClassifier)
mlp_keras.compile(loss="categorical_crossentropy", optimizer="adam", metrics=["accuracy"])
%time mlp_keras.fit(X_train, y_train, batch_size=100, epochs=10, validation_split=0.1)
# Show the accuracy score on the test set
mlp_keras.evaluate(X_test, y_test, verbose=0)[1]
Model: "sequential_1"
┏━━━━━━━━━━━━━━━━━━━━━━━━━━━━━━━━━━━┳━━━━━━━━━━━━━━━━━━━━━━━━━━┳━━━━━━━━━━━━━━━┓ ┃ Layer (type) ┃ Output Shape ┃ Param # ┃ ┡━━━━━━━━━━━━━━━━━━━━━━━━━━━━━━━━━━━╇━━━━━━━━━━━━━━━━━━━━━━━━━━╇━━━━━━━━━━━━━━━┩ │ dense_1 (Dense) │ (None, 28, 28, 16) │ 32 │ ├───────────────────────────────────┼──────────────────────────┼───────────────┤ │ dense_2 (Dense) │ (None, 28, 28, 16) │ 272 │ ├───────────────────────────────────┼──────────────────────────┼───────────────┤ │ dense_3 (Dense) │ (None, 28, 28, 10) │ 170 │ └───────────────────────────────────┴──────────────────────────┴───────────────┘
Total params: 474 (1.85 KB)
Trainable params: 474 (1.85 KB)
Non-trainable params: 0 (0.00 B)
Visualizing a convolutional neural network¶
To visualize a convolutional layer, we can apply a similar technique to plot the weights for each layer. Below are the 32 convolutional kernels learned by the first Conv2D
layer.
fig, axs = plt.subplots(nrows=4, ncols=8, figsize=(10, 5))
conv2d = model.layers[0].weights[0].numpy()
vmin = conv2d.min()
vmax = conv2d.max()
for ax, coef in zip(axs.ravel(), conv2d.T):
ax.matshow(coef[0].T, vmin=vmin, vmax=vmax)
for y in range(kernel_size[0]):
for x in range(kernel_size[1]):
# Display the weight values rounded to 1 decimal place
ax.text(x, y, round(coef[0, x, y], 1), va="center", ha="center")
ax.set_axis_off()
The remaining Conv2D
and Dense
layers become much harder to visualize because they have so many weights to examine. So let's instead visualize how the network activates in response to a sample image. The first plot below shows the result of convolving each of the above kernels on a sample image. The kernels above act as edge detectors.
# Construct a debugging model for extracting each layer activation from the real model
activations = models.Model(
inputs=model.inputs,
# Only include the first 4 layers (conv2d, max_pooling2d, conv2d_1, max_pooling2d_1)
outputs=[layer.output for layer in model.layers[:4]],
).predict(X_train[0:1])
# Show how the input image responds to a convolution using the very first filter (kernel) above
plt.imshow(activations[0][0, ..., 0], cmap="gray")
1/1 ━━━━━━━━━━━━━━━━━━━━ 0s 58ms/step
<matplotlib.image.AxesImage at 0x7917a1fa7a90>
Let's compare this result to another kernel by examining the table of filters above and changing the last indexing digit to a different value between 0 and 31.
plt.imshow(activations[0][0, ..., 1], cmap="gray")
The activations from this first layer are passed as inputs to the MaxPooling2D
second layer, and so forth. We can visualize this whole process by creating a plot that shows how the inputs flow through the model.
images_per_row = 8
for i, activation in enumerate(activations):
# Assume square images: image size is the same width or height
assert activation.shape[1] == activation.shape[2]
size = activation.shape[1]
# Number of features (filters, learned kernels, etc) to display
n_features = activation.shape[-1]
n_cols = n_features // images_per_row
# Tile all the images onto a single large grid; too many images to display individually
grid = np.zeros((size * n_cols, images_per_row * size))
for row in range(images_per_row):
for col in range(n_cols):
channel_image = activation[0, ..., col * images_per_row + row]
grid[col * size:(col + 1) * size, row * size:(row + 1) * size] = channel_image
# Display each grid with the same width
scale = 1.2 / size
plt.figure(figsize=(scale * grid.shape[1], scale * grid.shape[0]))
plt.imshow(grid, cmap="gray")
plt.title(model.layers[i].name)
plt.grid(False)
What patterns do you notice about the visual representation of the handwritten digit as we proceed deeper into the convolutional neural network?