CSV Data¶
In this lesson, we'll review the dictionary features and learn about the CSV data file format. By the end of this lesson, students will be able to:
- Identify the list of dictionaries corresponding to some CSV data.
- Loop over a list of dictionaries (CSV rows) and access dictionary values (CSV columns).
import doctest
Review: Dictionary functions¶
Dictionaries, like lists, are also mutable data structures so they have functions to help store and retrieve elements.
d.pop(key)
removeskey
fromd
.d.keys()
returns a collection of all the keys ind
.d.values()
returns a collection of all the values ind
.d.items()
returns a collection of all(key, value)
tuples ind
.
There are different ways to loop over a dictionary.
dictionary = {"a": 1, "b": 2, "c": 3}
for key in dictionary:
print(key, dictionary[key])
a 1 b 2 c 3
for k,v in dictionary.items():
print(k, v)
a 1 b 2 c 3
dictionary.pop("a")
1
dictionary
{'b': 2, 'c': 3}
None in Python¶
In the lesson on File Processing, we saw a function to count the occurrences of each token in a file as a dict
where the keys are words and the values are counts.
Let's debug the following function most_frequent
that takes a dictionary as input and returns the word with the highest count. If the input were a list, we could index the zero-th element from the list and loop over the remaining values by slicing the list. But it's harder to do this with a dictionary.
Python has a special None
keyword, like null
in Java, that represents a placeholder value.
def most_frequent(counts):
"""
Returns the token in the given dictionary with the highest count, or None if empty.
>>> most_frequent({"green": 2, "eggs": 6, "and": 3, "yam": 2})
'eggs'
>>> most_frequent({}) # None is not displayed as output
"""
max_word = None
for word in counts:
if max_word is None or counts[word] > counts[max_word]:
max_word = word
return max_word
doctest.run_docstring_examples(most_frequent, globals())
Loop unpacking¶
When we need keys and values, we can loop over and unpack each key-value pair by looping over the dictionary.items()
.
dictionary = {"a": 1, "b": 2, "c": 3}
for key, value in dictionary.items():
print(key, value)
a 1 b 2 c 3
Loop unpacking is not only useful for dictionaries, but also for looping over other sequences such as enumerate
and zip
. enumerate
is a built-in function that takes a sequence and returns another sequence of pairs representing the element index and the element value.
with open("poem.txt") as f:
for i, line in enumerate(f.readlines()):
print(i, line[:-1])
0 she sells 1 sea 2 shells by 3 the sea shore
zip
is another built-in function that takes one or more sequences and returns a sequence of tuples consisting of the first element from each given sequence, the second element from each given sequence, etc. If the sequences are not all the same length, zip
stops after yielding all elements from the shortest sequence.
arabic_nums = [ 1, 2, 3, 4, 5]
alpha_nums = ["a", "b", "c", "d", "e"]
roman_nums = ["i", "ii", "iii", "iv", "v"]
for arabic, alpha, roman in zip(arabic_nums, alpha_nums, roman_nums):
print(arabic, alpha, roman)
1 a i 2 b ii 3 c iii 4 d iv 5 e v
Comma-separated values¶
In data science, we often work with tabular data such as the following table representing the names and hours of some of our TAs.
Name | Hours |
---|---|
Diana | 10 |
Thrisha | 15 |
Yuxiang | 20 |
Sheamin | 12 |
A table has two main components to it:
- Rows corresponding to each entry, such as each individual TA.
- Columns corresponding to (required or optional) fields for each entry, such as TA name and TA hours.
A comma-separated values (CSV) file is a particular way of representing a table using only plain text. Here is the corresponding CSV file for the above table. Each row is separated with a newline. Each column is separated with a single comma ,
.
Name,Hours
Diana,10
Thrisha,15
Yuxiang,20
Sheamin,12
We'll learn a couple ways of processing CSV data in this course, first of which is representing the data as a list of dictionaries.
staff = [
{"Name": "Yuxiang", "Hours": 20},
{"Name": "Thrisha", "Hours": 15},
{"Name": "Diana", "Hours": 10},
{"Name": "Sheamin", "Hours": 12},
]
staff
[{'Name': 'Yuxiang', 'Hours': 20}, {'Name': 'Thrisha', 'Hours': 15}, {'Name': 'Diana', 'Hours': 10}, {'Name': 'Sheamin', 'Hours': 12}]
To see the total number of TA hours available, we can loop over the list of dictionaries and sum the "Hours" value.
total_hours = 0
for ta in staff:
total_hours += ta["Hours"]
total_hours
57
What are some different ways to get the value of Thrisha's hours?
for ta in staff:
if ta["Name"] == "Thrisha":
print(ta["Hours"])
15
Poll Question: select the right option
staff[1]["Hours"]
staff["Hours"][1]
staff["Thrisha"]["Hours"]
staff["Hours"]["Thrisha"]
staff[1]["Hours"]
15
Reading CSV files using Python's built-in csv package¶
Suppose we have a dataset of earthquakes around the world stored in the CSV file earthquakes.csv
.
import csv
earthquakes = []
with open("earthquakes.csv") as f:
reader = csv.DictReader(f)
for row in reader:
earthquakes.append(row)
earthquakes[:5]
[{'id': 'nc72666881', 'year': '2016', 'month': '7', 'day': '27', 'latitude': '37.6723333', 'longitude': '-121.619', 'name': 'California', 'magnitude': '1.43'}, {'id': 'us20006i0y', 'year': '2016', 'month': '7', 'day': '27', 'latitude': '21.5146', 'longitude': '94.5721', 'name': 'Burma', 'magnitude': '4.9'}, {'id': 'nc72666891', 'year': '2016', 'month': '7', 'day': '27', 'latitude': '37.5765', 'longitude': '-118.85916670000002', 'name': 'California', 'magnitude': '0.06'}, {'id': 'nc72666896', 'year': '2016', 'month': '7', 'day': '27', 'latitude': '37.5958333', 'longitude': '-118.99483329999998', 'name': 'California', 'magnitude': '0.4'}, {'id': 'nn00553447', 'year': '2016', 'month': '7', 'day': '27', 'latitude': '39.3775', 'longitude': '-119.845', 'name': 'Nevada', 'magnitude': '0.3'}]
csv.DictWriter
also exists; you can do the following to write a row into a csv file:
writeheader()
: Write a row with the field names (as specified in the constructor) to the writer’s file object.writerow(row)
orwriterows(rows)
: Write the row/rows parameter to the writer’s file object.
Here, row
is a dictionary and rows
is a list of dictionaries.
Practice: Largest earthquake place¶
Write a function largest_earthquake_place
that takes the earthquake data
represented as a list of dictionaries and returns the name of the location that experienced the largest earthquake. If there are no rows in the dataset (no data at all), return None
.
id | year | month | day | latitude | longitude | name | magnitude |
---|---|---|---|---|---|---|---|
nc72666881 | 2016 | 7 | 27 | 37.672 | -121.619 | California | 1.43 |
us20006i0y | 2016 | 7 | 27 | 21.515 | 94.572 | Burma | 4.9 |
nc72666891 | 2016 | 7 | 27 | 37.577 | -118.859 | California | 0.06 |
nc72666896 | 2016 | 7 | 27 | 37.596 | -118.995 | California | 0.4 |
nn00553447 | 2016 | 7 | 27 | 39.378 | -119.845 | Nevada | 0.3 |
For example, considering only the data shown above, the result would be "Burma"
because it had the earthquake with the largest magnitude (4.9).
def largest_earthquake_place(path):
"""
Returns the name of the place with the largest-magnitude earthquake in the specified CSV file.
>>> largest_earthquake_place("earthquakes.csv")
'Northern Mariana Islands'
"""
earthquakes = []
with open(path) as f:
reader = csv.DictReader(f)
for row in reader:
earthquakes.append(row)
largest_earthquake = None
for earthquake in earthquakes:
# for i in range(len(earthquakes)):
# earthquake = earthquakes[i]
# for i, earthquake in enumerate(earthquakes):
if largest_earthquake is None or float(earthquake["magnitude"]) > float(largest_earthquake["magnitude"]):
largest_earthquake = earthquake
return largest_earthquake["name"]
doctest.run_docstring_examples(largest_earthquake_place, globals())
Let's see another solution done with a library "pandas".
import pandas as pd
def largest_earthquake_place_pandas(path):
"""
Returns the name of the place with the largest-magnitude earthquake in the specified CSV file.
>>> largest_earthquake_place_pandas("earthquakes.csv")
'Northern Mariana Islands'
"""
earthquakes = pd.read_csv(path)
return earthquakes.loc[earthquakes["magnitude"].idxmax()]["name"]
doctest.run_docstring_examples(largest_earthquake_place_pandas, globals())
earthquakes = pd.read_csv("earthquakes.csv")
earthquakes.head()
id | year | month | day | latitude | longitude | name | magnitude | |
---|---|---|---|---|---|---|---|---|
0 | nc72666881 | 2016 | 7 | 27 | 37.672333 | -121.619000 | California | 1.43 |
1 | us20006i0y | 2016 | 7 | 27 | 21.514600 | 94.572100 | Burma | 4.90 |
2 | nc72666891 | 2016 | 7 | 27 | 37.576500 | -118.859167 | California | 0.06 |
3 | nc72666896 | 2016 | 7 | 27 | 37.595833 | -118.994833 | California | 0.40 |
4 | nn00553447 | 2016 | 7 | 27 | 39.377500 | -119.845000 | Nevada | 0.30 |
type(earthquakes)
pandas.core.frame.DataFrame
earthquakes = []
with open("earthquakes.csv") as f:
reader = csv.DictReader(f)
for row in reader:
earthquakes.append(row)
for i in earthquakes:
print(type(i))
break
<class 'dict'>