Due: 11:59pm on Monday October 12, 2020. Submit via Gradescope. (REQUIRED survey)
Learning Objectives:
Python is an easy-to-use but powerful programming language that is particularly well-suited to quickly creating small programs.
VS Code is more than just a code editor; it is a simple but powerful IDE, or "integrated development environment", which lets you edit, run, navigate, and debug Python code.
Download the file hw1.py [Tip: To download, right click this link and select "Save link as" or if you click through to see the file in your browser, just right click and select "Save as" or "Save Page as" or whatever wording your browser uses.]
Note: you should NOT make use of any features that we have not discussed in class, unless it is specifically endorsed in the assignment specification. (Such as math.sqrt for problem 1 of this homework).
Note: you should NOT post any of your code onto the discussion board or let other students see your code. If you have questions or problems with your code, try making a private discussion post, sending an email to staff, or attending office hours.
For problems in this homework, you will edit your local copy of the hw1.py file. You may do your work by editing and running hw1.py (we recommend this approach), or by typing code at the Python interpreter and copying it into the appropriate part of hw1.py when you are satisfied with it. When you have completed this homework, running the hw1.py file should compute the answers to all the problems, and print the following output (with the ____ replaced by the values you calculated). Please make your output match the following exactly.
Problem 1 solution follows: Root 1: ____ Root 2: ____ Problem 2 solution follows: 1/2: ____ 1/3: ____ 1/4: ____ 1/5: ____ 1/6: ____ 1/7: ____ 1/8: ____ 1/9: ____ 1/10: ____ Problem 3 solution follows: Triangular number 10 via loop: ____ Triangular number 10 via formula: ____ Problem 4 solution follows: 10!: ____ Problem 5 solution follows: 10!: ____ 9!: ____ 8!: ____ 7!: ____ 6!: ____ 5!: ____ 4!: ____ 3!: ____ 2!: ____ 1!: ____ Problem 6 solution follows: e: ____
Don't forget to include documentation (source code comments, on a line starting with #) as appropriate in file hw1.py.
1 plus 1 equals 2Here's some Python code that will do that:
n = 1 print(str(n) + " plus " + str(n) + " equals " + str(n + n))You can also use:
n = 1 print(str(n), "plus", str(n), "equals", str(n + n))Note that in the first case, I'm explicitly inserting spaces when I want them, but in the second case, the commas add spaces for me automatically. In the second case it is not necessary to call str() on n and n + n. The following would also work fine and be simpler.
n = 1 print(n, "plus", n, "equals", n + n)
You can print a blank line by calling just print() (and giving it
nothing to print).
Compute and print both roots of the quadratic equation with the smaller root first: 3 x2-5.86 x+ 2.5408.
Hint: recall that the roots of a quadratic equation ax2+bx+c are x=
| −b ± √ b2 − 4ac |
| 2a |
Hint: use the math.sqrt function to compute the square root. (If you are using the Python interpreter, you need to first do import math. This already appears as a commment in the hw1.py file that you will be editing, so you just need to uncomment that line to have everything set up.)
Use a for loop to print the decimal representations of 1/2, 1/3, ..., 1/10, one on each line.
Use a for loop to compute the 10th triangular number. The nth triangular number is defined as 1+2+3+...+n. (You can also compute the nth triangular number as n*(n+1)/2. Use this formula to double-check that your loop is correct.)
Hint: This outline is an almost-complete solution. You only have to replace each ellipsis by an expression.
n = 10
triangular = 0
for i in ...:
triangular = ...
print("Triangular number", n, "via loop:", triangular)
print("Triangular number", n, "via formula:", n * (n + 1) / 2)
Your code should be able to correctly calculate the 11th, 12th, or any other triangular
number just by changing the first line to set n to 11, 12, or any other
number. Be sure the code you submit calculates the triangle number for n = 10.
Using the range
function should help you accomplish this.
Use a for loop to compute 10!, the factorial of 10. Recall that the factorial of n is 1*2*3*...*n. [Note: you may not use the math.factorial() function for this problem or any other problem in this homework. You should also NOT use recursion. (If you do not know what that means, do not worry because you should not use it :-)]
Hint: Your answer will be similar to your answer to "Problem 3: Triangular numbers".
As in Problem 3, your code should be able to calculate 11!, 12!, or
any other number's factorial just by changing the first line to set n
to 11, 12, or any other number.
Be sure the code you submit calculates the factorial for n = 10.
Write code to print the first 10 factorials, in reverse order. In other words, write code that prints 10!, then prints 9!, then prints 8!, ..., then prints 1!. Its literal output will be:
10!: 3628800 9!: 362880 8!: 40320 7!: 5040 6!: 720 5!: 120 4!: 24 3!: 6 2!: 2 1!: 1
The first line of your solution should assign a variable num_lines to 10. Then, as in Problems 3 and 4, the rest of the code should print the correct number of lines and correct factorial on each line for values other than 10 just by setting num_lines to a different value.
Hint: Use two nested for loops.
The outer loop sets the value of n
to the values num_lines, num_lines-1, num_lines-2, ..., 1, in succession.
Then, the body of that loop
is itself a loop — exactly your solution to "Problem 4: Factorial",
without the first line n = 10 that hard-codes the value of n.
Compute the following value:
1 + 1/1! + 1/2! + 1/3! + 1/4! + ... + 1/10!
The value should be close to e (≈ 2.71828), the base of the natural logarithms.
Hint: The easiest way to solve this is with two nested for loops. It is possible, but tricky, to compute this using only one for loop. That is not necessary for this assignment.
Hint: Copy your solution to "Problem 5: Multiple factorials", then modify it. Rather than printing the factorials, you will add their reciprocals to a running total, then print that total at the end.
Hint: don't try to work the very first "1 +" into your loop; do it outside the loops (either at the very beginning or the very end of the outer loop).
You are almost done!
Now you're done!