Employee
/ \
/ \
Clerical Professional
| / \
| / \
Secretary Lawyers Engineers
|
|
Legal Secretary
Everyone in the company is an employee, but we divide them into clerical versus
professional employees. Among the professionals, we have lawyers and
engineers. Among the clericals we have secretaries and a variation of a
secretary known as a legal secretary. The idea is that this is part of a
company's hierarchy of employees. Obviously an actual company would have many
other kinds of employees as well.I mentioned that most companies have an employee orientation that all employees attend. Suppose that at that orientation there is a 20-page booklet given out that describes general employee procedures (insurance, retirement, vacations, etc). By default, an employee would assume that those are the policies that apply to that employee. But what tends to happen is that the day after the employee orientation they're told some more details. For example, the lawyers might have their own 3-page booklet. That booklet can have two kinds of things. It might have additional procedures that aren't part of the 20-page booklet. And it might have replacement procedures (what we call "overriding"). For example, they might tell a new lawyer, "I'm sure they told you yesterday at the orientation that when you want to take a vacation to fill out the yellow form. We don't use the yellow form here. We have our own form that's pink."
This is similar to what happens in Java with inheritance. You establish an inheritance relationship between two classes with the "extends" keyword in the class header:
class B extends A {
...
}
In our hierarchy diagram, we'd put B below A because it extends it:
A
|
|
B
We refer to B as a "subclass" of A and A as the "superclass" of B. This use of
sub and super is somewhat unfortunate because it has the opposite meaning to
how we use the words in English. With these inheritance hierarchies, we put
the more specialized version below (as the "sub") and the more generic one
above (as the "super"). For example, if we had a hierarchy for burgers and
cheeseburgers, we'd put the burger on top because it's the more generic one:
burger
|
|
cheeseburger
But think about this. Someone says, "You can have a cheeseburger or you can
have a super cheeseburger." I really like cheese, so I'd tend to ask for a
super cheeseburger. So imagine my surprise when I find that the super
cheeseburger has no cheese! Yet in the standard terminology we'd refer to
"burger" as the superclass of cheeseburger.Another pair of words that people sometimes use are to refer to the superclass as the "base" class and the subclass as the "derived" class. This is a little clearer in terms of the superclass being simpler (base). In fact, the C# programming language has a keyword "base" that has the same meaning as a Java keyword "super".
When you don't include an "extends" clause in a class header, the default is that the class extends a generic class known as Object. So in the hierarchy above, to be complete, we really should show that A exends Object:
Object
|
|
A
|
|
B
The Object class is something like the Employee or Vehicle terms that appear at
the top of the nonprogramming hiearchies we looked at. Every class that you
define extends Object one way or another, either directly, as in the A class,
or indirectly, as in the B class.Going back to our employee analogy, we talked about the idea of a 20-page manual that would apply to all employees. In an inheritance hierarchy, any state and behavior (i.e., any data fields and methods) in the superclass are automatically included in every subclass. In other words, saying "extends Foo" automatically gives a class all of the data fields and methods of the Foo class.
A subclass can do two things:
I mentioned two last points before we left the "employee" analogy. First I wanted to talk about when a substitute is appropriate. For example, you might imagine a hierarchy for vehicles that included bikes and cars. Among the cars you might have Hondas. Among the Hondas you might have Honda Accords. And among the Accords you might have a luxury version called an LX. And among the Accord LX models, you might have a variation that is known as "luxury package 319". We'd draw a hierarchy something like this to capture these variations:
Vehicle
/ \
/ \
Car Bike
|
|
Honda
|
|
Accord
|
|
Accord LX
|
|
Accord LX package 319
The point is that the most generic or simple description appears high in the
hierarchy. The more complex, more sophisticated objects appear low in the
hierarchy. That's because at each level we are adding potentially more and
more state and behavior.I used this vehicle hierarchy to talk about the notion of "substitutability". The question is, when can one object substitute for another? Inheritance should be used only when there is an "is-a" relationship where the more specialized object can substitute for the less specialized one. So in this hierarchy, the Accord LX luxury package 319 can take the place of anything above it but the things above it can't take its place. This matches our intuition in most cases. If we were expecting a generic Accord and we instead got a luxury Accord, we're not going to complain. But if we paid for the luxury car and instead got the generic car, then we wouldn't be happy.
We also can't substitute across. If we were expecting a luxury Accord, we aren't going to be happy with a bike. Of course, the analogy isn't perfect. In real life if we were expecting a bike, we might be satisfied with a luxury Accord instead, even though with inheritance hierarchies, that wouldn't be allowed.
I said that in programming we think of each of these different entries as "roles". The idea is that an object can fill many roles. An Accord LX luxury package 319 can fill the role of an Accord LX luxury package 319 because it is one. But it can also fill the role of an ordinary Accord LX and it can also fill the role of a generic Accord and it can also fill the role of a Honda and it can fill the role of a car and it can fill the role of vehicle. In general, an object call fill every role that appears as you go up the inheritance chain to the top.
In terms of our simple inheritance hierarchy with class B that extends class A, think about the following situations. The simple cases are where we have variables and objects of the same type. Obviously we can say:
A x = new A();
B y = new B();
But what happens if the variable type and the object type don't match?
A x = new B();
B y = new A();
One of these is legal and one is not and it comes from the inheritance
relationship. Remember that B extends A:
A
|
|
B
That means that A is the simpler, more generic object and B is the more
sophisticated, more complex object. In particular, a B object can substitute
for an A object. In other words, a B object can fill the role of a B object or
the role of an A object. But the opposite is not true. An A object cannot
fill the role of a B object. This is like our generic Accord versus our luxury
Accord. The luxury Accord is a reasonable substitute for the generic, but not
the other way around. So given our two lines of code, the first is okay but
the second is illegal:
A x = new B(); // okay, B can fill A role
B y = new A(); // not okay, A cannot fill B role
I considered one last question before moving on to Java examples. I said
suppose that you are running a temp agency and you charge people $10 per hour
for a secretary and $15 an hour for a legal secretary. One day a customer asks
you to send over a secretary and you find that you have no generic secretaries
to send over, but you have a legal secretary that otherwise wouldn't be working
that day. So you decide to send the legal secretary even though the request
was for a generic secretary. This works because of the notion of
substituting. A legal secretary can substitute for a secretary. But suppose
that during a coffee break the employer figures out that the person you sent
over is actually a legal secretary and the employer says, "Great, I have some
legal secretarial work I want you to do."I asked if this is okay and people said no. Why not? That employer asked for a secretary and is paying $10 an hour. I happened to send over someone who can do more, but that doesn't mean that employer has the right to change the contract and ask the person to do more than the contract is for. If that employer wants the person to do legal secretary work, then we need to renegotiate the contract and that employer needs to pay $15 an hour for that work.
I said that this is exactly what is happening in Java when you use a class cast. You are renegotiating the contract for what you can ask that object to do. I said we'd see examples of this in the sample problems we were about to do.
I then showed people how these ideas apply to actual code by looking at handout #15. By looking at the class headers and the "extends" clauses, we were able to figure out that the inheritance hierarchy looks like this:
One
/ \
/ \
Two Three
|
|
Four
I then suggested that we make a table that keeps track of what definition (if
any) each class has for method1, method2 and method3. Starting with the class
One, we find that it defines method1 as producing the output "One1". It has no
definition for method2 and method3. That means that the "One" role does not
include a method2 or method3. This will be important later in solving this
problem. So our table starts out like this:
method1 method2 method3
One One1 --- ---
The Two class provides a definition for method3 that prints out "Two3". It has
no other definitions, but it inherits a method1 from One that prints "One1".
It has no method2. So now the table looks like this:
method1 method2 method3
One One1 --- ---
Two One1 --- Two3
The Three class provides a definition for method2 that prints "Three2" and then
calls method1. There is no definition for method1 in this class, but it
inherits one from the One class that prints "One1". Since method2 prints
"Three2" and then calls method1, you might be inclined to say that its output
is two lines: Three2/One1. But that won't always be the case because of what's
known as "polymorphism". Java is a dynamic language where methods can be
redefined. So for a Three object, method2 prints those two lines of output.
But it won't necessarily behave that way for all objects because method1 might
be redefined. The Three class had no definition for method3. So now our table
looks like this:
method1 method2 method3
One One1 --- ---
Two One1 --- Two3
Three One1 Three2 ---
method1()
Finally, the Four class defines a method1 and a method3. In method1 of the
Four class we see something new, a use of the keyword "super". In this
context, super is being used to call an overridden method. This class is
giving a new definition to method1, but in doing so, it can call the original
version of the method in the superclass by using the keyword "super". You can
think of the keyword "super as an alternative to "this". If you say
"super.method1()" you are asking for the version of method1 in the superclass.
If you say "this.method1()" or just "method1", you're asking for the version of
method1 in this class.We spent some time talking about the details of super. I mentioned that it is statically bound in that you know exactly what method is being called. A minute ago we were careful not to make assumptions about which method1 would be called because that involved a call on "this.method1" where polymorphism enters into things. Here we know exactly what method is being called, the version of method1 in the superclass of the four class. Actually, there is no definition of method1 in the superclass of Four (class Three), so to find it, we keep looking up the inheritance chain until we find the definition in the class One.
So we know that method1 prints out "Four1/One1". Method2 is the inherited method that prints out "Three2" and then calls method1. And method3 prints out "Four3". So the Four class is the only class that has all three methods defined. So our final version of the table looks like this:
method1 method2 method3
One One1 --- ---
Two One1 --- Two3
Three One1 Three2 ---
method1()
Four Four1 Three2 Four3
One1 method1()
There are several things to notice about this table. First of all, think in
terms of the four roles: One, Two, Three and Four. The One role defines just a
method1; the Two role has a method1 and method3; the Three role has a method1
and method2 and the Four role has all three of method1, method2 and method3.
Also notice what a call on method2 will produce for a Three object versus a
Four object. Remember that method2 includes a call on method1 and this is
determined polymorphically. For a Three object, method1 produces the output
"One1", so a call on its method2 would produce two lines of output
(Three2/One1). For a Four object, method1 produces two lines of output, so a
call on its method2 would produce three lines of output (Three2/Four1/One1).
The same method call can end up calling different methods. That's what
polymorphism is all about (poly for "many" and morphism for "forms", so a
single method call can take "many forms").
We then looked at the rest of the problem. It involves several variables that
are defined and a series of calls using those variables. I mentioned that
there is a three step process to go through to figure out these calls:
I pointed out that the first six problems involved calling method1 on each of the six variables without any casting going on. The first question you have to consider is whether you pass the compiler check. To figure that out, you have to look at the types of the variables. The types of the objects don't matter to the compiler. The variables determine the contract. The variables of type One and Three are okay because both the One class and the Three class include a method1. But the two variables of type Object are a problem because the Object class does not include a method1. Even though the objects themselves can do this, the contract was for a generic Object, so the compiler is going to complain. This is an exact parallel of our employer who asked for a secretary and got a legal secretary. Even though the legal secretary can do more sophisticated work, the employer isn't allowed to ask for that because the contract is for a $10/hour generic secretary, not for a legal secretary.
So the fifth and six answers are "compiler error". The first four pass the compiler and have no casting, so we don't have to worry about runtime errors. The only thing left is to figure out what the individual objects do when method1 is called.
We then looked at the first casting example:
((Two)var1).method2();
The variable var1 is declared to be of type "One", so in the absence of a cast,
we'd be looking at the One role to figure out this contract. But there is a
cast, so we use that instead. We are casting to Two, which means we have
renegotiated the contract. So the question becomes, does the Two role include
a method2? The answer is no. So even with this cast, we get a compiler error
(the role we have contracted for does not include this method).But what about the next one:
((Three)var1).method2();
Here we are using a cast to Three to renegotiate the contract. So the question
becomes, does the Three role include a method2? The answer is yes. So we pass
the compiler (step 1). Then we ask whether the cast is actually legal (step
2). What kind of object do we have? The variable var1 is referring to a Two
object. Can a Two object be cast to a Three? In other words, can a Two
substitute for a Three? The answer is no. This would be like giving someone a
bicycle when they were expecting an Accord (it's a cast across, which is
illegal). So even though we pass the compiler, we don't pass the runtime
system. So this generates a runtime error.As a final example, we considered this problem:
((Four)var5).method2();
We have a cast, so we look at the Four role to determine whether this is legal
as far as the compiler is concerned (step 1). The answer is yes. The Four
role includes a method2. So we pass the compiler. But what about the second
step? We have to consider whether the cast is legal. The actual object is a
Three object. Can a Three object substitute for a Four object? The answer is
no. A Four object can substitute for a Three, but not the other way around.
So this generates a runtime error because of the illegal cast.The odd thing about this example is that the actual object would be able to execute method2. If we had instead cast to Three, it would work:
((Three)var5).method2();
So in a sense we have "overcast" in this case. We didn't need to claim that it
will be a Four. We only needed to claim that it was a Three. But if you
overclaim, Java will call you on it. It will make sure that all of your casts
actually work out.Below is a list of all of the problems from the section handout with a brief description of each answer.
| Call | Output | Discussion |
|---|---|---|
| var1.method1(); | One1 | variable is of type One, One role includes method1, no cast, actual object is a Two which writes out "One1" when method1 is called |
| var2.method1(); | One1 | variable is of type One, One role includes method1, no cast, actual object is a Three which writes out "One1" when method1 is called |
| var3.method1(); | Four1/One1 | variable is of type One, One role includes method1, no cast, actual object is a Four which writes out "Four1/One1" when method1 is called |
| var4.method1(); | Four1/One1 | variable is of type Three, Three role includes method1, no cast, actual object is a Four which writes out "Four1/One1" when method is called |
| var5.method1(); | compiler error | variable is of type Object, Object role does not include method1 |
| var6.method1(); | compiler error | variable is of type Object, Object role does not include method1 |
| var4.method2(); | Three2/Four1/One1 | variable is of type Three, Three role includes method2, no cast, actual object is a Four which writes out "Three2/Four1/One1" when method2 is called (note that method2 calls its method1 polymorphically, which is why this output includes "Four1") |
| var4.method3(); | compiler error | variable is of type Three, Three role does not include method3 (even though the object itself is a Four that is capable of performing this action) |
| ((Two)var1).method2(); | compiler error | because of cast we pay attention to it rather than the variable type (because we have renegotiated the contract), cast is to Two, Two role does not include method2 |
| ((Three)var1).method2(); | runtime error | cast is to Three, Three role includes method2 so we pass the compiler, but actual object is a Two which can't fill the Three role (casting across the hierarchy, like asking someone to accept a bike when they were expecting a car), so we get a runtime error |
| ((Two)var1).method3(); | Two3 | cast is to Two, Two role includes method3, actual object is a Two which cal fill the Two role, so the cast is okay, and a Two object writes "Two3" when its method3 is called |
| ((Four)var2).method1(); | runtime error | cast is to Four, Four role includes method1, actual object is a Three which can't fill the Four role; this was, in essence, a stupid cast to do because it isn't necessary, but if you tell this kind of lie, Java will complain |
| ((Four)var3).method1(); | Four1/One1 | cast is to Four, Four role includes method1, actual object is a Four which can fill the Four role, so cast is okay and a Four object writes "Four1/One1" when method1 is called |
| ((Four)var4).method3(); | Four3 | cast is to Four, Four role includes method3, actual Object is a Four, which can fill the Four role, so cast is okay and a Four object writes "Four3" when method3 is called |
| ((One)var5).method1(); | One1 | cast is to One, One role includes method1, actual object is a Three, which can fill the One role, so cast is okay and a Three object writes "One1" when method1 is called |
| ((Four)var5).method2(); | runtime error | cast is to Four, Four role includes method2, actual object is a Three which can't fill the Four role |
| ((Three)var5).method2(); | Three2/One1 | cast is to Three, Three role includes method2, actual object is a Three which can fill the Three role and a Three object writes "Three2/One1" when method2 is called |
| ((One)var6).method1(); | One1 | cast is to One, One role includes method1, actual object is a One which can fill the One role, so cast is okay and a One object writes "One1" when method1 is called |
| ((One)var6).method2(); | compiler error | cast is to One, One role does not include method2 |
| ((Two)var6).method3(); | runtime error | cast is to Two, Two role includes method3, actual object is a One, which can't fill the Two role |