common/conf common/conf
Except where otherwise noted, the contents of this document are Copyright 2013 Stuart Reges and Marty Stepp.
lab document created by Marty Stepp, Stuart Reges and Whitaker Brand
Goals for today:
Scanner
and File
objects to read input data from filesScanner
breaks input into tokensString
sRecall that although we use ==
to compare the values of primitive types, such as ints, doubles,
and chars
. However, ==
has a different meaning for Strings
: it evaluates to true
when one String is set to equal another (ex. String a = b
). To see whether two Strings have the same value, we instead use .equals()
.
Enter true
or false
for the following:
String a = "hello"; String h = "h"; String b = h + "ello"; |
// a == b? false |
String a = "hello"; String h = "h"; String b = h + "ello"; |
// a.equals(b)? true |
String a = "world"; String b = a; |
// a == b? true |
String a = "world"; String b = a; |
// a.equals(b)? true |
File
sSo far, we've used Scanners to read user input. Now, we're going to look at using Scanners to read over files!
A File
object allows you to interact with actual files on your computer. Make sure to put any file you want to read with a Scanner in the same folder as the program that wants to use it!
// necessary to use Files import java.io.*; // makes a File object, holding the same info as the file named "actualNameOfFile" File fileVariableName = new File("actualNameOfFile"); // a Scanner that reads over the File! Scanner fileScanner = new Scanner(fileVariableName);
Method name | Parameters | Description |
---|---|---|
exists()
|
a String file name
|
returns true if a file w/ the given file name exists in the same folder.
|
Which of the following choices is the correct syntax for declaring
a Scanner
to read the file example.txt
in the
current directory?
Scanner
methodsMethod name | Description |
---|---|
next()
|
reads and returns the next token as a String
|
nextLine()
|
reads and returns as a String all the characters up to
the next new line (\n )
|
nextInt()
|
reads and returns the next token as an int , if
possible
|
nextDouble()
|
reads and returns the next token as double , if
possible
|
hasNext()
|
returns true if there is still a token in
the Scanner
|
hasNextLine()
|
returns true if there is still at least one line left
to be read in the Scanner
|
hasNextInt()
|
returns true if the next token can be read as
an int
|
hasNextDouble()
|
returns true if the next token can be read as
an double
|
4.2 abc 4The following methods would read this as:
Method | What happened? | What's going on? |
---|---|---|
nextInt()
|
java.util.InputMismatchException | tried to read next token 4.2, couldn't process it as an int. |
nextDouble()
|
returns 4.2 as a double. | tried to read next token, succeeded because it could be read as a double. |
next()
|
returned "4.2" as a String. | read the next word as a String. |
nextLine()
|
returns "4.2 abc 4" as a String. | read the whole next line as a String. |
How many tokens are in the
following String
?
3
welcome...to the matrix.
What are the tokens that the String
breaks up into?
How many tokens are in the
following String
?
9
in fourteen-hundred 92 columbus sailed the ocean blue :)
What are the tokens that the String
breaks up into?
Scanner
practice
The next couple problems are about a file called readme.txt
that has the following contents:
6.7 This file has several input LINES! 10 20
What would be the output from the following code, as it would appear on the console?
Scanner input = new Scanner(new File("readme.txt")); System.out.println(input.next()); // 6.7 System.out.println(input.next()); // This System.out.println(input.next()); // file
Scanner
practice
Input file: readme.txt
6.7 This file has several input LINES! 10 20
What would be the output for the following code? If there would be an error, write error .
Note: these problems are all independent. Thisinput
Scanner is not the same as the one on the previous slide!
Scanner input = new Scanner(new File("readme.txt")); System.out.println(input.nextDouble()); // 6.7 System.out.println(input.nextDouble()); // error
Scanner
practice
Input file: readme.txt
6.7 This file has several input LINES! 10 20
What would be the output for the following code? If there would be an error, write error .
Scanner input = new Scanner(new File("readme.txt"));
while (!input.hasNextInt()) {
input.next();
}
System.out.println(input.nextInt()); // 10
Scanner
practice
Input file: readme.txt
6.7 This file has several input LINES! 10 20
What would be the output for the following code? If there would be an error, write error .
Scanner input = new Scanner(new File("readme.txt")); System.out.println(input.nextLine()); // 6.7 This file has System.out.println(input.nextLine()); // several input System.out.println(input.nextLine()); // LINES!
4.2 abc 4The following methods would read this as:
Method | Returned | Why? |
---|---|---|
hasNextInt()
|
false | the next token is a double, and thus cannot be read as an integer. |
hasNextDouble()
|
true | the next token is a double! |
hasNext()
|
true | the next token can be read as a String! |
hasNextLine()
|
true | there exists a line of input! |
.hasNext()
caution
.hasNext()
methods only check the type of the next token. .next()
methods consume tokens, changing what token the Scanner is looking at next! For each of the following, enter the output if the loop terminates, or write infinite
if the loop loops forever!
Consider the following as part of input.txt
Jello world :)
Scanner input = new Scanner(new File("input.txt")); while (input.hasNext()) { String nextWord = input.next(); System.out.print(nextWord + " "); } |
Jello world :) |
|
Scanner input = new Scanner(new File("input.txt")); while (input.hasNext()) { System.out.println("hi"); } |
infinite |
flipLines
Write a method named flipLines
that accepts
a Scanner
holding an input file and writes to the console the same
file's contents with each pair of lines reversed in order. If the input file has an odd number of lines, the last line should be printed in its original position! For example, if
the file contains:
Twas brillig and the slithy toves did gyre and gimble in the wabe. All mimsey were the borogroves, and the mome raths outgrabe. The EndYour method should produce the following output:
did gyre and gimble in the wabe. Twas brillig and the slithy toves and the mome raths outgrabe. All mimsey were the borogroves, The End
When you work with File
s, the Java
compiler gets concerned that you might be trying to access a File
that doesn't exist. So any method that uses File
s must declare that it might throw a FileNotFoundException: this basically tells Java that if the desired "actualNameOfFile" cannot be found, it's okay to crash.
Every method that directly or indirectly calls a method that works with File
s also needs to declare that it might throw a FileNotFoundException.
File
. Then A() and B() must declare that they might throw a FileNotFoundException.
File
. Then A() and B() and C() must all declare that they might throw a FileNotFoundException
.public static void main(String[] args) throws FileNotFoundException { ... }
import
statements and a declaration that the method might throw a FileNotFoundException
to
the code.
import java.io.*; // for File import java.util.*; // for Scanner public class Words { public static void main(String[] args) throws FileNotFoundException { int wordCount = 0; Scanner input = new Scanner(new File("wordinput.txt")); // your code goes here ... while (input.hasNext()) { String word = input.next(); wordCount++; } System.out.println("Total words = " + wordCount); } }
.next()
vs .nextLine()
.next()
reads and returns the next token as a String. Tokens are separated by white space.
.nextLine()
reads and returns the next line as a String. A line is all the characters up to the next \n
(line break).Scanner
should only ever read its input using either .next()
(mixing with .nextDouble()
and .nextInt()
and .nextBoolean()
is fine), or using .nextLine()
.
Consider the following problem:
We already know how to read full lines or individual words from a Scanner. Now we need a new strategy: we need to read lines from the input, and then we need to somehow read word-by-word through each line.
We can do this by creating a second Scanner! So far, we've used Scanners to read user input and to read Files. Scanners can also read over Strings!
Scanner fileScannerName = new Scanner(new File("fileName")) while (fileScannerName.hasNextLine()) { String line = fileScannerName.nextLine(); // reads the next line from the input file Scanner lineScanner = new Scanner(line); while (lineScanner.hasNext()) { String word = lineScanner.next(); // reads the next word from the input line ... } }
coinFlip
Write a method named coinFlip
that accepts
a Scanner
for an input file of coin flips that are heads (H)
or tails (T). Consider each line to be a separate set of coin flips and
output the number and percentage of heads in that line. If it is more than
50%, print "You win!". Consider the following file:
H T H H T T t t T h H h
For the input above, your method should produce the following output:
3 heads (60.0%) You win! 2 heads (33.3%) 1 heads (100.0%) You win!Note: to print a "%" using printf, say
System.out.printf("%%");
1 2 3 4 5 6 7 8 9 10 11 12 13 14 15 |
// Counts the total lines and words in the given input scanner. public static void countWords(Scanner input) { Scanner input = new Scanner(new File("example.txt")); int lineCount = 0; int wordCount = 0; while (input.nextLine()) { String line = input.line(); // read one line lineCount++; while (line.next()) { // count tokens in line String word = lineScan.hasNext; wordCount++; } } } |
The above attempted solution to Practice-It problem
"countWords
" has a few errors.
Open Practice-It, copy/paste this code into it, and fix
the errors. Complete the code so that it passes the test cases.
1 2 3 4 5 6 7 8 9 10 11 12 13 14 15 16 17 18 19 20 |
// Counts the total lines and words in the given input scanner. public static void countWords(Scanner input) { |
In this exercise we will practice the jGRASP debugger using the Case Study example from the end of Chapter 6. To download this example, follow these steps:
ZipLookup.java
and zipcode.txt
.
Right-click the file names and choose the option to save the link in whatever folder you have been using for lab work.
Make sure to save them in the same folder.
ZipLookup.java
in jGRASP.
You might try using your own ZIP code and a relatively small radius like 0.5 miles.
The program takes a while to run because it has to search a large data file.
continued on the next slide...
ZipLookup
program.
find
.
Then it shows all matches in the method named showMatches
.
We want to debug showMatches
.
continued on the next slide...
What zip code are you interested in? 20500 And what proximity (in miles)? 0.3 20500: Washington, DC zip codes within 0.3 miles: 20045 Washington, DC, 0.26 miles 20500 Washington, DC, 0.00 miles 20501 Washington, DC, 0.27 miles 20502 Washington, DC, 0.27 milesSet a break point on the
while
loop itself.
Then enter the the values of lat1
and long1
(latitude and longitude of the White House ZIP code).
lat1 |
38.894781 |
|
long1 |
-77.036122 |
continued on the next slide...
Clear your previous break point and set a new break point inside on the printf
inside the if
.
Then hit the resume button that looks like a play button and fill in the table below with the values for zip
, lat2
, and long2
.
zip |
lat2 |
long2 |
---|---|---|
20045 | 38.896599 | -77.0319 |
20500 | 38.894781 | -77.036122 |
20501 | 38.89872 | -77.036198 |
20502 | 38.89872 | -77.036198 |
runningSum
Write a static method called runningSum
that
accepts as a parameter a Scanner
holding a sequence of real
numbers and that outputs the running sum of the numbers followed by the
maximum running sum. For example if the Scanner
contains the
following data:
3.25 4.5 -8.25 7.25 3.5 4.25 -6.5 5.25
Your method should produce the following output:
running sum = 3.25 7.75 -0.5 6.75 10.25 14.5 8.0 13.25 max sum = 14.5
Click on the check-mark above to try out your solution in Practice-it!
printDuplicates
Write a method printDuplicates
that accepts a Scanner
for an input file.
Examine each line for consecutive occurrences of the same token on the same line and print each duplicated token along how many times it appears consecutively. For example the file:
hello how how are you you you you I I I am Jack's Jack's smirking smirking smirking smirking smirking revenge one fish two fish red fish blue fish bow wow wow yippee yippee yo yippee yippee yay yay yay
leads to the following console output:
how*2 you*4 I*3 Jack's*2 smirking*5 wow*2 yippee*2 yippee*2 yay*3
mostCommonNames
Write a method mostCommonNames
that accepts a Scanner
for an input file with names on each line separated by spaces. Some names appear multiple times, if they do, they are listed consecutively. For example:
Benson Eric Eric Marty Kim Kim Kim Jenny Nancy Nancy Nancy Paul Paul Stuart Stuart Stuart Ethan Alyssa Alyssa Helene Jessica Jessica Jessica Jessica Jared Alisa Yuki Catriona Cody Coral Trent Kevin Ben Stefanie Kenneth
For each line, print the most commonly occurring name. If there's a tie, use the first name that had that many occurrences.
Most common: Kim Most common: Jessica Most common: Jared
Also return the total number of unique names in the whole file (e.g. 23 for the above input).
frequentFlier
Write a method frequentFlier
that accepts a Scanner
for an input file of ticket type / mileage pairs and reports how many frequent-flier miles the person earned.
For example, given the input below, your method should return 15600 (2*5000 + 1500 + 100 + 2*2000).
firstclass 5000 coach 1500 coach 100 firstclass 2000 discount 300
If you finish all the exercises, try out our Practice-It web tool. It lets you solve Java problems from our Building Java Programs textbook.
You can view an exercise, type a solution, and submit it to see if you have solved it correctly.
Choose some problems from the book and try to solve them!