Except where otherwise noted, the contents of this document are Copyright 2011 Stuart Reges and Marty Stepp.
lab document created by Marty Stepp, Stuart Reges, and Whitaker Brand
Goals for today:
Random
objects to produce random numbersboolean
expressions and variables to represent logical true/false expressionsRandom
methods
To use these methods, you need a variable of type Random
in
scope:
Random randy = new Random();
int aRandomNumber = randy.nextInt(10); // 0-9
Method name | Returns... |
---|---|
nextInt()
|
a random integer |
nextInt(max)
|
a random integer between 0 (inclusive) and max (exclusive) |
nextDouble()
|
a random real number between 0.0 and 1.0 |
nextBoolean()
|
a random boolean value: true
or false
|
Fill in the boxes to produce expressions that will generate random numbers in the provided ranges.
Assume that the following Random
variable has been declared:
Random rand = new Random();
Example: a random integer from 1 to 5 inclusive: |
rand.nextInt(5)
+
1
|
a random integer from 0 to 3 inclusive: |
rand.nextInt(4)
|
a random integer from 5 to 10 inclusive: |
rand.nextInt(6)
+
5
|
a random integer from -4 to 4 inclusive: |
rand.nextInt(9)
-
4
|
a random even integer from 16 to 28 inclusive: (Hint: To get only even numbers, scale up.) |
rand.nextInt(7)
*
2
+
16
|
boolean
type
The boolean
type represents logical values of true
or false
. Combine boolean
expressions with logical operators &&
(and), ||
(or), and !
(not).
Example:
boolean test1 = 7 < 10; // true boolean test2 = (1 == 2); // false if ((test1 || test2) && 2 + 2 != 5) { System.out.print("hello"); // output: hello }
String
methods with boolean
resultsMethod name | Description |
---|---|
string.equals(string)
|
whether the two strings are identical |
string.equalsIgnoreCase(string)
|
whether the two strings are identical, ignoring capitalization |
string.startsWith(string)
|
whether this string begins with the characters of the given string |
string.endsWith(string)
|
whether this string ends with the characters of the given string |
string.contains(string)
|
whether the characters of the given string occur within this string |
String name = "Professor Smith"; if (name.startsWith("Prof")) { System.out.println("When are your office hours?"); }
Write the result of each expression as either true
or false
, given the following variables.
int x = 12; int y = 7; int z = 28; String s = "mid term";
x < 14 |
true |
|
!(x % 2 < 1) |
false |
|
x < y || x < z |
true |
|
z / x < x / y * x |
true |
|
s.length() == y |
false |
|
s.toUpperCase().equals("MID TERM") |
true |
|
!s.equals("mid term") || x * y != z |
true |
|
s.substring(z / x).length() > y |
false |
Identify whether each assertion is always/never/sometimes true
at each point.
x > y |
z == 0 |
x == y |
|
---|---|---|---|
A | SOMETIMES | ALWAYS | SOMETIMES |
B | SOMETIMES | SOMETIMES | NEVER |
C | ALWAYS | NEVER | NEVER |
D | NEVER | NEVER | NEVER |
E | NEVER | SOMETIMES | ALWAYS |
public static void mystery(int x, int y) { int z = 0; // Point A while (x != y) { // Point B z++; if (x > y) { // Point C x = x / 10; } else { // Point D y = y / 10; } } // Point E System.out.println(x + " " + y + " " + z); }
You can also solve this problem in Practice-It by clicking on the check-mark above.
The CSE 142 midterm exam is usually very similar to the format of the practice exams. The following kinds of problems are often found on the exam:
To solve each problem, you will need to use various concepts and syntax taught throughout the course so far, such as System.out.println, expressions, variables, parameters, return, if/else, for/while loops, Scanner, and Random. Part of the challenge is in figuring out which tools to use and how to use them together to solve the problem at hand.
lastDigit
that returns the last digit
of an integer. For example, lastDigit(3572)
should
return 2
. It should work for negative numbers as well. For
example, lastDigit(-947)
should return 7
.
firstDigit
that returns the first digit
of an integer. For example, firstDigit(3572)
should
return 3
. It should work for negative numbers as well. For
example, firstDigit(-947)
should return 9
.
season
that takes two integers as
parameters representing a month and day and that returns a String
indicating the season for that month and day. Assume that months are
specified as an integer between 1 and 12 (1 for January, 2 for February,
and so on) and that the day of the month is a number between 1 and 31.
"Winter"
. If the date falls between 3/16 and 6/15,
you should return "Spring"
. If the date falls between 6/16
and 9/15, you should return "Summer"
. And if the date falls
between 9/16 and 12/15, you should return "Fall"
.
Write a method named makeGuesses
that will output random
numbers between 1 and 50 inclusive until it outputs one of at least 48.
Output each guess and the total number of guesses made. Below is a sample
execution:
guess = 43 guess = 47 guess = 45 guess = 27 guess = 49 total guesses = 5
Try solving this problem in Practice-It! from the link above.
Write a method named allDigitsOdd
that returns whether every
digit of a positive integer is odd. Your method should
return true
if the number consists entirely of odd digits
and false
if any of its digits are even. 0, 2, 4, 6, and 8
are even digits, and 1, 3, 5, 7, 9 are odd digits.
For example, allDigitsOdd(135319)
returns true
but allDigitsOdd(9145293)
returns false
.
Hint: You can pull apart a number into its digits using /
10
and % 10
.
Write a method named hopscotch
that accepts
an integer parameter for a number of "hops" and prints a hopscotch board of
that many hops.
For example, the call hopscotch(3);
would produce the
following output:
1 2 3 4 5 6 7 8 9 10
Try to solve this problem in Practice-It: click on the check-mark above!
Write a method hasMidpoint
that accepts three
integers as parameters, and returns true
if one of the numbers
is the midpoint of the other two and returns false
otherwise.
For example, the call hasMidpoint(3, 7, 5)
would
return true
because one of the parameters (5) is the midpoint
of the other two (3 and 7).
Try to solve this problem in Practice-It: click on the check-mark above!
1 2 3 4 5 6 7 8 9 10 11 12 13 14 15 16 17 18 |
public class StringOops { public static void main(String[] args) { Scanner console = new Scanner(System.in); System.out.print("Type your name: "); String name = console.nextString(); process(name); } public static void process(string "name") { if (name == Whitaker) { System.out.println("You must be really awesome."); } replace("a", "e"); toUppercase(name); name.substring(0, 3); System.out.println(name + " has " + name.length + " letters"); } } |
nextString
should be next
string
should be String
name
should not be in quotesWhitaker
should be in quotes==
; must
use .equals
replace
without specifying a string
object (name
)toUppercase
should be
toUpperCase
name.
should come
before toUpperCase
, not passed as a parameter to itname =
to store the result
of toUpperCase
name =
to store the result
of substring
()
when
calling length
public class StringOops { public static void main(String[] args) { Scanner console = new Scanner(System.in); System.out.print("Type your name: "); String name = console.next(); process(name); } public static void process(String"name") { if (name.equals("Whitaker")) { System.out.println("You must be really awesome."); } name = name.replace("a", "e"); name = name.toUpperCase(); name = name.substring(0, 3); System.out.println(name + " has " + name.length() + " letters"); } }
The following code from Microsoft's Zune music player calculates today's date from the years/days passed since 1980. But all Zune players locked up on Dec 31 2008. Why? Download ZuneBug.java and modify it to fix the bug.
int days = getTotalDaysSince1980(); // pretend this method exists int year = 1980; while (days > 365) { // subtract out years if (isLeapYear(year)) { // pretend this method exists if (days > 366) { days = days - 366; year++; } } else { days = days - 365; year++; } }
The bug occurs when the current year is a leap year and there are exactly
366 days left (i.e., if today is Jan 1 on a year after a leap year). The
code gets stuck in an infinite loop with days == 366
because
the while
test is true
but the if (days
> 366)
is false
. Here is a fixed version:
int days = getTotalDaysSince1980(); // pretend this method exists int year = 1980; while (days > 365 || (isLeapYear(year) && days > 366)) { if (isLeapYear(year)) { days = days - 366; } else { days = days - 365; } year++; }
Write a method before
that takes as parameters two month/day
combinations and that returns whether or not the first date comes before
the second date (true
if the first month/day comes before the
second month/day, false
if it does not). The method will take
four integers as parameters that represent the two month/day combinations.
The first integer in each pair represents the month and will be a value between 1 and 12 (1 for January, 2 for February, etc, up to 12 for December). The second integer in each pair represents the day of the month (a value between 1 and 31). One date is considered to come before another if it comes earlier in the year.
Solve this problem in Practice-It by clicking on the check-mark above.
Write a method sameDashes
that takes two strings as parameters
and that returns whether or not they have dashes in the same places
(returning true
if they do and returning false
otherwise). For example, below are four pairs of strings of equal length
that have the same pattern of dashes. Notice that the last pair has no
dashes at all.
string 1: "hi--there-you." "-15-389" "criminal-plan" "abc" string 2: "12--(134)-7539" "-xy-zzy" "(206)555-1384" "9.8"To be considered a match, the strings must have exactly the same number of dashes in exactly the same positions. The Strings might be of different length.
Solve this problem in Practice-It by clicking on the check-mark above.
Write a method flip
that takes a Random
object as
a parameter and that prints information about a coin-flipping simulation.
Your method should use the Random
object to produce a sequence
of simulated coin flips, printing whether each flip comes up "heads" or
"tails". Each outcome should be equally likely. Your method should stop
flipping when you see three heads in a row.
Solve this problem in Practice-It by clicking on the check-mark above.
This attempted solution to Self-Check 5.15 (isVowel
) has
several problems:
// Returns whether the given string represents a vowel: // a, e, i, o, or u, case insensitively. public static boolean isVowel(String s) { if (s == "a") { return true; } else if (s == "e") { return true; } else if (s == "i") { return true; } else if (s == "o") { return true; } else if (s == "u") { return true; } else { return false; } }
Open Practice-It from the link above, copy/paste this code into it, then see the next slide.
Fix the following aspects of the code:
public static boolean isVowel(String s) { s = s.toLowerCase(); if (s.equals("a") || s.equals("e") || s.equals("i") || s.equals("o") || s.equals("u")) { return true; } else { return false; } }
The above can be improved. "Boolean Zen" version:
public static boolean isVowel(String s) { s = s.toLowerCase(); return s.equals("a") || s.equals("e") || s.equals("i") || s.equals("o") || s.equals("u"); }
If you finish all the exercises, try out our Practice-It web tool. It lets you solve Java problems from our Building Java Programs textbook.
You can view an exercise, type a solution, and submit it to see if you have solved it correctly.
Choose some problems from the book and try to solve them!