while
loops, fencepost, Random numbers, boolean logic, midterm practicewhile
loops, fencepost, Random numbers, boolean logic, midterm practiceExcept where otherwise noted, the contents of this document are Copyright 2010 Stuart Reges and Marty Stepp.
lab document created by Whitaker Brand and Marty Stepp
Goals for today:
while
loops for indefinite repetition
Random
objects to produce random numbers
boolean
expressions and variables to represent logical true/false expressions
while
loop mysteryFill in the boxes at right with the output produced by each method call.
public static void mystery(int x, int y) { int z = 0; while (x % y != 0) { x = x / y; z++; System.out.print(x + ", "); } System.out.println(z); } |
|
digitSum
that accepts an integer as a parameter and returns the sum of the digits of that number. For example, the call digitSum(29107)
returns 2+9+1+0+7 or 19. For negative numbers, return the same value that would result if the number were positive. For example, digitSum(-456)
returns 4+5+6 or 15. The call digitSum(0)
returns 0.
use / 10
and % 10
operations.)
public static int digitSum(int n) { n = Math.abs(n); // handle negatives int sum = 0; while (n > 0) { int lastDigit = n % 10; sum = sum + lastDigit; // add last digit to sum n = n / 10; // remove last digit from n } return sum; }
Random
Methods
To use these methods, you need a variable of type Random
in scope:
Random randy = new Random();
int aRandomNumber = randy.nextInt(10); // 0-9
Method name | Returns... |
---|---|
nextInt()
|
a random integer |
nextInt(max)
|
a random integer between 0 (inclusive) and max (exclusive) |
nextDouble()
|
a random real number between 0.0 and 1.0 |
nextBoolean()
|
a random boolean value: true or false
|
Random
variable has been declared:
Random rand = new Random();
Example: a random integer from 1 to 5 inclusive: |
rand.nextInt(5)
+
1
|
a random integer from 0 to 3 inclusive: |
rand.nextInt(4)
|
a random integer from 5 to 10 inclusive: |
rand.nextInt(6)
+
5
|
a random integer from -4 to 4 inclusive: |
rand.nextInt(9)
-
4
|
a random even integer from 16 to 28 inclusive: (Hint: To get only even numbers, scale up.) |
rand.nextInt(7)
*
2
+
16
|
Write the result of each expression as either true
or false
, given the following variables. Recall the logical operators: &&
(and), ||
(or), !
(not).
int x = 12; int y = 7; int z = 28; String s = "mid term";
x < 14 |
true |
|
!(x % 2 < 1) |
false |
|
x < y || x < z |
true |
|
z / x < x / y * x |
true |
|
s.length() == y |
false |
|
s.toUpperCase().equals("MID TERM") |
true |
|
!s.equals("mid term") || x * y != z |
true |
|
s.substring(z / x).length() > y |
false |
Write a method named makeGuesses
that will output random numbers between 1 and 50 inclusive until it outputs one of at least 48. Output each guess and the total number of guesses made. Below is a sample execution:
guess = 43 guess = 47 guess = 45 guess = 27 guess = 49 total guesses = 5
Try solving this problem in Practice-It! from the link above.
Identify whether each assertion is always/never/sometimes true
at each point.
x > y |
z == 0 |
x == y |
|
---|---|---|---|
A | SOMETIMES | ALWAYS | SOMETIMES |
B | SOMETIMES | SOMETIMES | NEVER |
C | ALWAYS | NEVER | NEVER |
D | NEVER | NEVER | NEVER |
E | NEVER | SOMETIMES | ALWAYS |
public static void mystery(int x, int y) { int z = 0; // Point A while (x != y) { // Point B z++; if (x > y) { // Point C x = x / 10; } else { // Point D y = y / 10; } } // Point E System.out.println(x + " " + y + " " + z); }
Write a method named allDigitsOdd
that returns whether every digit of a positive integer is odd. Your method should return true
if the number consists entirely of odd digits and false
if any of its digits are even. 0, 2, 4, 6, and 8 are even digits, and 1, 3, 5, 7, 9 are odd digits.
For example, allDigitsOdd(135319)
returns true
but allDigitsOdd(9145293)
returns false
.
Hint: You can pull apart a number into its digits using / 10
and % 10
.
Write a method named hopscotch
that accepts an integer parameter for a number of "hops" and prints a hopscotch board of that many hops.
For example, the call hopscotch(3);
would produce the following output:
1 2 3 4 5 6 7 8 9 10
Try solving this problem in Practice-It: click on the check-mark above!
Write a method hasMidpoint
that accepts three integers as parameters, and returns true
if one of the numbers is the midpoint of the other two and returns false
otherwise.
For example, the call hasMidpoint(3, 7, 5)
would return true
because one of the parameters (5) is the midpoint of the other two (3 and 7).
Try to solve this problem in Practice-It: click on the check-mark above!
Write a method named longestName
that reads names typed by the user and prints the longest name (the name that contains the most characters) in the format shown below. Your method should accept a console Scanner
and an integer n as parameters and should then prompt for n names.
A sample execution of the call longestName(console, 4)
might look like the following:
name #1? roy name #2? DANE name #3? sTeFaNiE name #4? Erik Stefanie's name is longest
Try to solve this problem in Practice-It: click on the check-mark above!
1 2 3 4 5 6 7 8 9 10 11 12 13 14 15 16 17 18 |
public class StringOops { public static void main(String[] args) { Scanner console = new Scanner(System.in); System.out.print("Type your name: "); String name = console.nextString(); process(name); } public static void process(string "name") { if (name == Whitaker) { System.out.println("You must be really awesome."); } replace("a", "e"); toUppercase(name); name.substring(0, 3); System.out.println(name + " has " + name.length + " letters"); } } |
nextString
should be next
string
should be String
name
should not be in quotesWhitaker
should be in quotes==
; must use .equals
replace
without specifying a string object (name
)toUppercase
should be toUpperCase
name.
should come before toUpperCase
, not passed as a parameter to itname =
to store the result of toUpperCase
name =
to store the result of substring
()
when calling length
public class StringOops { public static void main(String[] args) { Scanner console = new Scanner(System.in); System.out.print("Type your name: "); String name = console.next(); process(name); } public static void process(String"name") { if (name.equals("Whitaker")) { System.out.println("You must be really awesome."); } name = name.replace("a", "e"); name = name.toUpperCase(); name = name.substring(0, 3); System.out.println(name + " has " + name.length() + " letters"); } }
import java.util.*; // for Scanner public class ProcessName { public static void main(String[] args) { Scanner console = new Scanner(System.in); System.out.println("Type your name: "); // your code goes here System.out.println("Your name is: " + name); } }
Type your name: Jessica Miller
Your name is: Miller, J.
import java.util.*; // for Scanner public class ProcessName { public static void main(String[] args) { Scanner console = new Scanner(System.in); System.out.println("Type your name: "); // your code goes here String name = console.nextLine(); int space = name.indexOf(" "); String first = name.substring(0, space); String last = name.substring(space + 1, name.length()); String firstInitial = first.substring(0, 1); name = last + ", " + firstInitial + "."; System.out.println("Your name is: " + name); } }
ProcessName
program so that it re-prompts until the user types a name that is at least 5 letters total in length and has at least one space in it. Example:
Type your name: Joe Error, must be at least 5 chars with a space. Type your name: O K! Error, must be at least 5 chars with a space. Type your name: what Error, must be at least 5 chars with a space. Type your name: Tyler Durden Your name is: Durden, T.
import java.util.*; // for Scanner public class ProcessName2 { public static void main(String[] args) { Scanner console = new Scanner(System.in); System.out.println("Type your name: "); String name = console.nextLine(); while (name.length() < 5 || name.indexOf(" ") < 0) { System.out.println("Error, must be at least 5 chars with a space."); System.out.println("Type your name: "); name = console.nextLine(); } int space = name.indexOf(" "); String first = name.substring(0, space); String last = name.substring(space + 1, name.length()); String firstInitial = first.substring(0, 1); name = last + ", " + firstInitial + "."; System.out.println("Your name is: " + name); } }
repl
that accepts a String
and a number of repetitions as parameters and returns the String
concatenated that many times. For example, the call repl("hello", 3)
returns "hellohellohello"
. If the number of repetitions is 0 or less, an empty string is returned.
The following code from Microsoft's Zune music player calculates today's date from the years/days passed since 1980. But all Zune players locked up on Jan 1 2009. Why?
Download
ZuneBug.java
and modify it to fix the bug.
int days = getTotalDaysSince1980(); // pretend this method exists int year = 1980; while (days > 365) { // subtract out years if (isLeapYear(year)) { // pretend this method exists if (days > 366) { days = days - 366; year++; } } else { days = days - 365; year++; } }
The bug occurs when the current year is a leap year and there are exactly 366 days left (i.e., if today is Jan 1 on a year after a leap year). The code gets stuck in an infinite loop with days == 366
because the while
test is true
but the if (days > 366)
is false
. Here is a fixed version:
int days = getTotalDaysSince1980(); // pretend this method exists int year = 1980; while (days > 365 || (isLeapYear(year) && days > 366)) { if (isLeapYear(year)) { days = days - 366; } else { days = days - 365; } year++; }
Consider the following flawed method printLetters
, which accepts a String
as its parameter and attempts to print the letters of the String, separated by dashes. For example, the call of printLetters("Rabbit")
should print R-a-b-b-i-t
.
public static void printLetters(String text) { for (int i = 0; i < text.length(); i++) { System.out.print(text.substring(i, i + 1) + "-"); } System.out.println(); // to end the line of output }
What is wrong with the code? Paste the code in Practice-It! and fix it.
public static void printLetters(String text) { if (text.length() > 0) { System.out.print(text.substring(0, 1)); // fencepost for (int i = 1; i < text.length(); i++) { System.out.print("-" + text.substring(i, i + 1)); } System.out.println(); // to end the line of output } }
Write a method named printFactors
that accepts an integer as its parameter and uses a fencepost loop to print the factors of that number, separated by the word "and"
. For example, the call printFactors(24)
should print as the following output:
1 and 2 and 3 and 4 and 6 and 8 and 12 and 24
You may assume that the parameter value passed is greater than 0.
swapPairs
that accepts a String
as a parameter and returns that String
with each pair of adjacent letters reversed. If the String
has an odd number of letters, the last letter is unchanged. For example, the call swapPairs("forget")
should return "ofgrte"
and the call swapPairs("hello there")
should return "ehll ohtree"
.
This attempted solution to Self-Check 5.15 (isVowel
) has several problems:
// Returns whether the given string represents a vowel: // a, e, i, o, or u, case insensitively. public static boolean isVowel(String s) { if (s == "a") { return true; } else if (s == "e") { return true; } else if (s == "i") { return true; } else if (s == "o") { return true; } else if (s == "u") { return true; } else { return false; } }
Open Practice-It from the link above, copy/paste this code into it, then see the next slide.
Fix the following aspects of the code:
public static boolean isVowel(String s) { s = s.toLowerCase(); if (s.equals("a") || s.equals("e") || s.equals("i") || s.equals("o") || s.equals("u")) { return true; } else { return false; } }
The above can be improved. "Boolean Zen" version:
public static boolean isVowel(String s) { s = s.toLowerCase(); return s.equals("a") || s.equals("e") || s.equals("i") || s.equals("o") || s.equals("u"); }
If you finish all the exercises, try out our Practice-It web tool. It lets you solve Java problems from our Building Java Programs textbook.
You can view an exercise, type a solution, and submit it to see if you have solved it correctly.
Choose some problems from Chapter 5 and try to solve them!