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Key to CSE142 Sample Midterm handout #17
Fall 2004
1. Expression Value
---------------------------------------------
2.0 * 3/4 + 1 2.5
(11 % 3 + 1.0)/2 1.5
2.4 + 11 % 7/3 3.4
3 + 2 + "-" + 4 * 2 + 5 5-85
6.8/2 + 21/2/(5 - 3) 8.4
2. Parameter Mystery. The program produces the following output.
Many a student in the computer of fred
Many a computer in the department of major
Many a department in the honor of fred
Many a baz in the bar of foo
Many a major in the department of computer
3. Method Call Value Returned
--------------------------------------
mystery(1) 1
mystery(3) 2
mystery(4) 3
mystery(5) 5
mystery(6) 8
4. y < x y == 0 count > 0
+---------------------+---------------------+---------------------+
Point A | sometimes | sometimes | never |
+---------------------+---------------------+---------------------+
Point B | always | sometimes | sometimes |
+---------------------+---------------------+---------------------+
Point C | always | always | always |
+---------------------+---------------------+---------------------+
Point D | sometimes | sometimes | sometimes |
+---------------------+---------------------+---------------------+
Point E | never | sometimes | sometimes |
+---------------------+---------------------+---------------------+
5. One possible solution appears below.
public static void repeat(String s, int n) {
System.out.print("[");
if (n > 0) {
System.out.print(s);
for (int i = 2; i <= n; i++)
System.out.print(", " + s);
}
System.out.println("]");
}
6 One possible solution appears below.
public static double tax(double salary) {
if (salary <= 7150)
return 0.1 * salary;
else if (salary < 29050)
return 715 + 0.15 * (salary - 7150);
else if (salary < 70350)
return 4000 + 0.25 * (salary - 29050);
else
return 14325 + 0.28 * (salary - 70350);
}
7. One possible solution appears below.
public static int log2(int n) {
int power = 0;
while (n > 1) {
n /= 2;
power++;
}
return power;
}
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