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Compute
s=1/3(2(p-1)(q-1)+1) then
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compute
Cs = Kr×c + T
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That is …
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The remainders (C) raised to
s power equal
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Kr times some (quotient) c no one cares
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about plus the original clear text number!
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So, raise the remainders to s, divide by Kr
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and PRESTO! the new remainder is the
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answer
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