3
Extension Axioms Revisited
Moreover, this is iff
Lemma Forall s0: m(ss0 ¹)
= 1
Proof:
Every ss0 is the conjunction of several expressions ss1¹,
where s1 states s0 over fewer variables, by repeating some of them.
ss0¹ = 8 x.¹(x))9 z. s0(x,z)
“not-so-loose”
extension
axiom
extension
axiom
ss0 = 8 x.9 z. s0(x,z)
“Loose”
extension
axiom
extension
axiom