5
Proof: PFP = PSPACE
•PFP + <  µ PSPACE  [ why ?  ]
•
•To show PSPACE µ PFP + <
proceed as before, but can’t define T0(p, t) because we can’t express t
•Instead define T0(p), T1(p), Hq(p) using a PFP
•Each new step recomputes these tables
•Make sure to define T0(p+1) = T0(p) etc whenever reaching an accepting state