// This program determines what year it is right now and what day of the year
// it is.  For a non-leap year, the day-of-year will be between 1 and 365.
// For a leap year, it will be between 1 and 366.
//
// This version has a bug.  It goes into an infinite loop on the 366th day
// of a leap year.  This happened to Zune players on 12/31/08 because they
// had similar code.

public class Days1 {
    public static void main(String[] args) {
        long millis = System.currentTimeMillis();

        // we subtract 1/3 to account for Pacific Time being 8 hours 
        // behind Greenwich Mean Time;
        double days = toDays(millis) - 1.0 / 3.0;
        System.out.println("millis = " + millis);
        System.out.println("days   = " + days);

        // we add 1 because 1/1/70 is day 1 of 1970, not day 0
        int day = (int) days + 1;
        // the zune bug will show up if you include this line of code:
        // day = 14245;
        int year = 1970;
                
        while (day > 365) {
            if (year % 4 == 0) {
                if (day > 366) {
                    day = day - 366;
                    year++;
                }
            } else {
                day = day - 365;
                year++;
            }
        }

        System.out.println("year   = " + year);
        System.out.println("day    = " + day);
    }

    // converts milliseconds to days
    public static double toDays(long millis) {
        return millis / 1000.0 / 60.0 / 60.0 / 24.0;
    }
}